Returning file names from a directory and sub-directory

Hi,

I found some code online to return filenames from a directory and it's sub-directories. What would be useful for me would be if the path for each file name is ommitted e.g. insted of C:/My Documented/test.m I just get test.m in the results.

any help much apreciated.

function fileList = getAllFiles(dirName)

dirData = dir(dirName);      %# Get the data for the current directory
dirIndex = [dirData.isdir];  %# Find the index for directories
fileList = {dirData(~dirIndex).name}';  %'# Get a list of the files
if ~isempty(fileList)
  fileList = cellfun(@(x) fullfile(dirName,x),...  %# Prepend path to files
                     fileList,'UniformOutput',false);
end
subDirs = {dirData(dirIndex).name};  %# Get a list of the subdirectories
validIndex = ~ismember(subDirs,{'.','..'});  %# Find index of subdirectories
                                             %#   that are not '.' or '..'
for iDir = find(validIndex)                  %# Loop over valid subdirectories
  nextDir = fullfile(dirName,subDirs{iDir});    %# Get the subdirectory path
  fileList = [fileList; getAllFiles(nextDir)];  %# Recursively call getAllFiles
end

end

[Matthew]

I played around and found the answer, simply remove the if ~isempty(fileList) fileList = cellfun(@(x) fullfile(dirName,x),... %# Prepend path to files fileList,'UniformOutput',false); end and it does what i want. hope this may be useful to others.

best wishes

Answer 1

[Image Analyst]

Use genpath() to get a list of folders and subfolders. Then use fullfile() and fileparts() as needed for whatever version of the filename you want.