Subscripted assignment dimension mismatch - Help

5 visualizzazioni (ultimi 30 giorni)
Hello everybody i have been trying to code a 1D wave problem using the Leap Frog Scheme but i am running into an error that i am not familiar with. Any suggestions?
freq = 1; % Hz
omega = 2*pi*freq; % angular speed m/s
c = 10; % m/s
amp = 1;
% Space
dx = 0.001;
xmax = 1; % domain of unit length
lambda = 0.05; % size of wave
k = 2*pi/lambda; % wavenumber
x = 0:dx:xmax;
Vx = length(x); % matrix of propagation in the x direction
u_0 = zeros(size(x));
% defining wave initial conditions
for i = 1:Vx;
if x(i) < lambda;
u_0(i) = (1 - cos(k*x(i)))*0.5;
else
break
end
end
%Time
dt = 0.01;
t = 0:dt:1;
Vt = length(t);
figure(1)
plot(x,u_0,'.-b');
axis([0 lambda 0 1])
phi = zeros(Vx,Vt);
for n = 1:Vx;
phi(1,i) = u_0(i);
phi(2,i) = u_0(i);
end
for i = 2:Vt
for n = 2:Vx-1
phi(i,n+1) = phi(i,n-1) + (u_0*(dt/dx))*(phi(i+1,n) - phi(i-1,n)/phi(i,n-1));
end
end

Risposta accettata

Sean de Wolski
Sean de Wolski il 12 Apr 2011
It means you're trying to put more (or less) elements in a place than you've indexed.
%E.g.
A = [2, 3]
B = magic(3)
B(1,1:3) = A; %your error
What line does it say the error occurred on and what do you do for indexing at that line?

Più risposte (1)

Walter Roberson
Walter Roberson il 12 Apr 2011
In your line
phi(i,n+1) = phi(i,n-1) + (u_0*(dt/dx))*(phi(i+1,n) - phi(i-1,n)/phi(i,n-1));
u_0 is a vector, so the right hand side is going to have a vector result, which you then try to store in to a single memory location.
Perhaps your right hand side should use u_0(i) ?
  2 Commenti
Francis Mboya
Francis Mboya il 12 Apr 2011
Thanks Walter, worked like a charm!!! I have been working on this for a week now and i was clueless. kudos
Francis Mboya
Francis Mboya il 13 Apr 2011
Hello Walter, I was wondering if there is a way to make the wave plot figure(1) move across the domain till it reaches xmax? Thanks

Accedi per commentare.

Tag

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by