Azzera filtri
Azzera filtri

can't plot

3 visualizzazioni (ultimi 30 giorni)
YoungWoo Choi
YoungWoo Choi il 26 Mag 2020
Risposto: VBBV il 8 Nov 2023
syms p1
th1 = 0
ap1 = 0
a1 = 0
b1 = 0.5
c1 = 0
R1z = [ cos(p1), -sin(p1),0, 0;
sin(p1), cos(p1), 0, 0;
0, 0, 1, 0;
0, 0, 0, 1];
M1y = [1, 0, 0, a1;
0, 1, 0, b1;
0, 0, 1, c1;
0, 0, 0, 1];
TM1 = R1z*M1y
syms ap2
th2 = 0
p2 = 0
a2 = 0
b2 = 0
c2 = 0.3
R2y = [ cos(ap2),0, -sin(ap2), 0;
0, 1, 0, 0;
sin(ap2), 0, cos(ap2), 0;
0, 0, 0, 1];
M2z = [1, 0, 0, a2;
0, 1, 0, b2;
0, 0, 1, c2;
0, 0, 0, 1];
TM2 = R2y*M2z
syms ap3
th3 = 0
ap3 = 0
a3 = 0
b3 = 0
c3 = 0.2
R3y = [ cos(ap3),0, -sin(ap3), 0;
0, 1, 0, 0;
sin(ap3), 0, cos(ap3), 0;
0, 0, 0, 1];
M3z = [1, 0, 0, a3;
0, 1, 0, b3;
0, 0, 1, c3;
0, 0, 0, 1];
TM3 = R3y* M3z
syms ap4
th4 = 0
p4 = 0
a4 = 0
b4 = 0
c4 = 0.2
R4y = [ cos(ap4),0, -sin(ap4), 0;
0, 1, 0, 0;
sin(ap4), 0, cos(ap4), 0;
0, 0, 0, 1];
M4z = [1, 0, 0, a3;
0, 1, 0, b3;
0, 0, 1, c3;
0, 0, 0, 1];
TM4 = R4y* M4z
TM1
T12=mtimes(TM1,TM2)
T123=mtimes(TM1,mtimes(TM2,TM3))
T1234=mtimes(TM1,mtimes(TM2,mtimes(TM3,TM4)))
%%ex.3.2
L1=0.5
L2=0.3
L3=0.2
for i=1:1:20
for j= 1:1:20
ap2=pi/10*i
p1=pi/10*j
ap3=pi/10*j
rrrrrx= -sin(p1)/2 %링크1의 x좌표
rrrrry=cos(p1)/2 %링크1의 y좌표
rrrrrz= 0 %링크1의 z좌표
rrrrx= -sin(p1)/2 - (3*cos(p1)*sin(ap2))/10 %링크2의 x좌표
rrrry= cos(p1)/2 - (3*sin(ap2)*sin(p1))/10 %링크2의 y좌표
rrrrz= (3*cos(ap2))/10 %링크2의 z좌표
rrrx= - sin(p1)/2 - (cos(p1)*sin(ap2))/2 %링크3의 x좌표
rrry= cos(p1)/2 - (sin(ap2)*sin(p1))/2 %링크3의 y좌표
rrrz= cos(ap2)/2 %링크3의 z좌표
rrx= - sin(p1)/2 - cos(p1)*((3*sin(ap2))/10 + sin(ap2)*(cos(ap4)/5 + 1/5) + (cos(ap2)*sin(ap4))/5) %링크4의 x좌표
rry= cos(p1)/2 - sin(p1)*((3*sin(ap2))/10 + sin(ap2)*(cos(ap4)/5 + 1/5) + (cos(ap2)*sin(ap4))/5) %링크4의 y좌표
rrz= (3*cos(ap2))/10 - (sin(ap2)*sin(ap4))/5 + cos(ap2)*(cos(ap4)/5 + 1/5) %링크4의 z좌표
rx=[rrrrrx,rrrrx,rrrx,rrx];
ry=[rrrrry,rrrry,rrry,rry]
rz=[rrrrrz,rrrrz,rrrz,rrz]
plot3(rx,ry,rz,'-');
axis([-2 2 -2 2 -2 2])
figure(3)
end
end
I'm kind of a new for matlab.. please help! i can't plot this simulation
  3 Commenti
YoungWoo Choi
YoungWoo Choi il 27 Mag 2020
Modificato: YoungWoo Choi il 27 Mag 2020
yes, ap2, ap3, ap4, p1 is a unknown values for the angle,. I think the range of p1 and ap2 ,3,4 is 2*pi, because its an angle(radian).
Image Analyst
Image Analyst il 27 Mag 2020
If yes, and you cannot convert them from symbolic to arrays with linspace(), then I can't run it because I don't have the Symbolic toolbox. If you make them arrays, I might have a chance.

Accedi per commentare.

Risposte (2)

VBBV
VBBV il 8 Nov 2023
syms p1 ap2 ap3 ap4
th1 = 0;
ap1 = 0;
a1 = 0;
b1 = 0.5;
c1 = 0;
R1z = [ cos(p1), -sin(p1),0, 0;
sin(p1), cos(p1), 0, 0;
0, 0, 1, 0;
0, 0, 0, 1];
M1y = [1, 0, 0, a1;
0, 1, 0, b1;
0, 0, 1, c1;
0, 0, 0, 1];
TM1 = R1z*M1y;
th2 = 0;
p2 = 0;
a2 = 0;
b2 = 0;
c2 = 0.3;
R2y = [ cos(ap2),0, -sin(ap2), 0;
0, 1, 0, 0;
sin(ap2), 0, cos(ap2), 0;
0, 0, 0, 1];
M2z = [1, 0, 0, a2;
0, 1, 0, b2;
0, 0, 1, c2;
0, 0, 0, 1];
TM2 = R2y*M2z;
th3 = 0;
ap3 = 0;
a3 = 0;
b3 = 0;
c3 = 0.2;
R3y = [ cos(ap3),0, -sin(ap3), 0;
0, 1, 0, 0;
sin(ap3), 0, cos(ap3), 0;
0, 0, 0, 1];
M3z = [1, 0, 0, a3;
0, 1, 0, b3;
0, 0, 1, c3;
0, 0, 0, 1];
TM3 = R3y* M3z;
th4 = 0;
ap4 = 0;
p4 = 0;
a4 = 0;
b4 = 0;
c4 = 0.2;
R4y = [ cos(ap4),0, -sin(ap4), 0;
0, 1, 0, 0;
sin(ap4), 0, cos(ap4), 0;
0, 0, 0, 1];
M4z = [1, 0, 0, a3;
0, 1, 0, b3;
0, 0, 1, c3;
0, 0, 0, 1];
TM4 = R4y* M4z;
TM1;
T12=mtimes(TM1,TM2);
T123=mtimes(TM1,mtimes(TM2,TM3));
T1234=mtimes(TM1,mtimes(TM2,mtimes(TM3,TM4)));
%%ex.3.2
L1=0.5;
L2=0.3;
L3=0.2;
hold on
for i=1:1:20
for j= 1:1:20
ap2=pi/10*i;
p1=pi/10*j;
ap3=pi/10*j;
ap4 = pi/10*j;
rrrrrx= -sin(p1)/2; %링크1의 x좌표
rrrrry=cos(p1)/2; %링크1의 y좌표
rrrrrz= 0 ; %링크1의 z좌표
rrrrx= -sin(p1)/2 - (3*cos(p1)*sin(ap2))/10; %링크2의 x좌표
rrrry= cos(p1)/2 - (3*sin(ap2)*sin(p1))/10; %링크2의 y좌표
rrrrz= (3*cos(ap2))/10; %링크2의 z좌표
rrrx= - sin(p1)/2 - (cos(p1)*sin(ap2))/2; %링크3의 x좌표
rrry= cos(p1)/2 - (sin(ap2)*sin(p1))/2; %링크3의 y좌표
rrrz= cos(ap2)/2; %링크3의 z좌표
rrx= - sin(p1)/2 - cos(p1)*((3*sin(ap2))/10 + sin(ap2)*(cos(ap4)/5 + 1/5) + (cos(ap2)*sin(ap4))/5); %링크4의 x좌표
rry= cos(p1)/2 - sin(p1)*((3*sin(ap2))/10 + sin(ap2)*(cos(ap4)/5 + 1/5) + (cos(ap2)*sin(ap4))/5); %링크4의 y좌표
rrz= (3*cos(ap2))/10 - (sin(ap2)*sin(ap4))/5 + cos(ap2)*(cos(ap4)/5 + 1/5); %링크4의 z좌표
rx=[rrrrrx,rrrrx,rrrx,rrx];
ry=[rrrrry,rrrry,rrry,rry];
rz=[rrrrrz,rrrrz,rrrz,rrz];
plot3(double(rx),double(ry),double(rz),'b.');
axis([-2 2 -2 2 -2 2])
end
end
% view(3)

Vaibhav Tomar
Vaibhav Tomar il 31 Mag 2020
Hey
Conversion to arrays might make it easier to analyse the specific issue with the execution. It might be better if you could assign some range for p1,ap2,etc.

Categorie

Scopri di più su Symbolic Math Toolbox in Help Center e File Exchange

Tag

Prodotti


Release

R2020a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by