how to get function value?

66 visualizzazioni (ultimi 30 giorni)
Ani Asoyan
Ani Asoyan il 3 Giu 2020
Commentato: Ani Asoyan il 3 Giu 2020
Hi I want to evaluate function and its derivative at a=2 , how to do that?
syms a
b=2
e=0.9
q=1.2
g=2
k=3
d=0.5
f=(q*b*e/a-d*e)/((q^2)*(e^2)/a+2*e*g)
diff(f)

Risposta accettata

madhan ravi
madhan ravi il 3 Giu 2020
df(a) = diff(f)
df(2)
  5 Commenti
madhan ravi
madhan ravi il 3 Giu 2020
Modificato: madhan ravi il 3 Giu 2020
P.S: You have some troubles with copying.
f(a) = (q*b*e/a-d*e)/((q^2)*(e^2)/a+2*e*g)
f(2)
Ani Asoyan
Ani Asoyan il 3 Giu 2020
oh I'm so bad at matlab :D .. thank you

Accedi per commentare.

Più risposte (1)

David Hill
David Hill il 3 Giu 2020
syms a;
b=2;
e=0.9;
q=1.2;
g=2;
k=3;
d=0.5;
f=(q*b*e/a-d*e)/((q^2)*(e^2)/a+2*e*g);
df=diff(f);
fvals=eval(subs(f,1:10));%evaluate f from 1:10 (if you want actual symetric value eleminate the eval function
dfvals=eval(subs(df,1:10));
  3 Commenti
madhan ravi
madhan ravi il 3 Giu 2020
Nah using eval(...) is o]absolutely not needed here! forget it!
Ani Asoyan
Ani Asoyan il 3 Giu 2020
I agree,, David Hill , thanks for the effort, but I think I'll go with the other answer, sorry

Accedi per commentare.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by