Calculating double integral for exponential function

Hi everyone! I'm trying to calculate this integral using Matlab but, being a beginner, I'm struggling a bit.
This is the code I attempted using the documentation, but by some reason the answer isn't correct. Any help improving it will be appreciated.
fun = (@(x,y) exp(x.^2));
xmin = @(y) y;
q = integral2(fun, 0, 1, xmin, 1);

2 Commenti

Could you explain why the result is wrong?
If calculated manually, the result of the integral gives 0.85914
However, when run through MATLAB, its 0.6035

Accedi per commentare.

 Risposta accettata

syms x y
fun = exp(x.^2)
Wanted = vpa(int(int(fun,x,y,1),y,0,1))
% however I’m not sure why it returns that result

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