how can i calculate in matlab

we borrowed $1000 at a 10% anual intrests rate. if we do not makre a payment for 2 years, and assuming there is no penalty for non payment, how much do we owe now?

[Ameer Hamza]

This isn't really a MATLAB problem. It is a finance problem. Also, it seems like homework. What have you already tried?

[lokesh m]

the answer isws 1210

[Alfred Jones Arokiaraj]

wrong answer . try in CI. answer will be 1.2100e+03

[Walter Roberson]

@Alfred Jones Arokiaraj

At the MATLAB command prompt give the command

format long g

now ask to display the result again.

Answer 1

[Atsushi Ueno]

simple interest:

1000 + (1000 * 0.1) * 2

compound interest:

1000 + 1000 * 0.1 + (1000 + 1000 * 0.1) * 0.1
or
1000 * (1 + 0.1) ^ 2

as function

simple interest:

function current = simple_interest(debt, rate, period)
  current = debt + (debt * rate) * period;
end

compound interest:

function current = compound_interest(debt, rate, period)
  current = debt * (1 + rate) ^ period;
end

[madhan ravi]

Answering homework question with full solution is discouraged in this forum.

[Atsushi Ueno]

I'm sorry. I'll be more careful from now on.

[Neha Jaiswal]

thank you. it was first question so i was unable to understand.

Answer 2

[Roopesh R Peter]

Compound the interest once a year:

debt = 1000 + 1000 * 0.1 + (1000 + 1000 * 0.1) * 0.1

[Rik]

(I moved the flag content to the answer body, since it shouldn't have been a tag)

Answer 3

[Shivani Dubey]

p = 1000
r = 10/100
n= 1
t = 2


S =(1.1)^2
debt = p* S

[ahmed hammad]

thanks i had a tried a different methode and it has the same result but it was rejected when i submitted it to COURSERA but when i tried to you know simplify it like you did it worked

Thanks.

[Shreyasi]

Annual interest?

Answer 4

[Medical Imaging]

The problem is simple and related to finance,

Borrowed_money = 1000;
Interest_rate = 10/100;
Delay_year = 2;
 
debt = Borrowed_money*(1+Interest_rate)^Delay_year

[Abdulrahman Farouq]

Thx so much

Answer 5

[Jayashri Patil]

clear "all"
clc
n=input('enter the number of different pipe size: ');
rho=input('enter the value of density: ');
Mu=input('enter the value of viscocity: ');
Q=input('enter the flowrate: ');
e=input('enter the epsilon: ');
g=input('enter the accleration gravity: ');

for i=1:n
   D(i)=input('enter the diameter of pipe: ','s');
   L=input('enter the length of pipe: ','s');
   KL(i)=input('enter the value of bends: ','s');
end
for i=1:n
    A(i)=pi*D(i)*D(i)/4;
    v(i)=Q/A(i);
ReynoldsNumber(i)=rho*v(i)*D(i)/Mu;
if  ReynoldsNumber(i) <2300
    f(i)=64/ReynoldsNumber(i);
elseif ReynoldsNumber(i) >4000
    c=@(f)(l/sqrt(f(i)))+(2*log10*(e/D(i)*3.7+2.51/ReynoldsNumber(i)*sqrt(f(i))));
    f(i)=fzero(c,[0.01,0.05]);
end
deltap(i)=(f(i)*(L(i)/D(i))*((rho*v(i)*v(i))/2)/1000); % pressure drop in kpa
HL(i)=(f(i)*(L(i)/D(i))+KL(i)*v(i)*v(i)/2*g); % head loss in m
end

[Jayashri Patil]

how to calculate pressure drop for n number of array using different daimetre pipe.

[Walter Roberson]

Please start your own Question about this, as it is not related to the question about calculation of interest.

[Jayashri Patil]

how to take nth number of inputs from user

[Rik]

You already posted a very similar question. Why not post a comment there with a follow-up question?