Randomization one of four triangles - Error: index out of bounds

2 visualizzazioni (ultimi 30 giorni)
Here is my code:
downtri = [50 0;0 50;-50 0];
uptri = [50 0;0 -50;-50 0];
righttri = [0 50;0 -50;50 0];
lefttri = [0 50;0 -50;-50 0];
arrarray = [downtri;uptri:lefttri:righttri];
arrdx1 = randi(4,1,1);
arrow1 = arrarray(arrdx1,:);
arrdx2 = randi(4,1,1);
while ismember(arrdx2, arrdx1)
arrdx2 = randi(4,1,1);
end
arrow2 = arrarray(arrdx2,:);
arrdx3 = randi(4,1,1);
while ismember(arrdx3, [arrdx1,arrdx2])
arrdx3 = randi(4,1,1);
end
arrow3 = arrarray(arrdx3,:);
arrdx4 = randi(4,1,1);
while ismember(arrdx4, [arrdx1,arrdx2,arrdx3])
arrdx4 = randi(4,1,1);
end
arrow4 = arrarray(arrdx4,:);
So the above is meant to randomize shape of a triangle with 4 different shape possibilities (it works great with randomizing color). However, when I try to randomize triangles I get this error message: "Attempted to access arrarray(4,:); index out of bounds because size(arrarray)=[3,2]. I think it means that basically the shape of the triangle won't fit into the matrix, but I'm not sure how to fix it.
Please help, :( :( :(

Risposta accettata

Walter Roberson
Walter Roberson il 24 Nov 2012
Modificato: Walter Roberson il 24 Nov 2012
Change
arrarray = [downtri;uptri:lefttri:righttri];
to
arrarray = [downtri;uptri;lefttri;righttri];
Warning: your triangles are all 3 x 2, and you are trying to store several of them in one array, but then you are accessing by row number rather than by triangle number.
Side note:
Have you considered replacing your code
arrdx4 = randi(4,1,1);
while ismember(arrdx4, [arrdx1,arrdx2,arrdx3])
arrdx4 = randi(4,1,1);
end
with
arrdx4 = setdiff(1:4, [arrdx1,arrdx2,arrdx3]);
?
  4 Commenti
Brett
Brett il 24 Nov 2012
Do you have any idea might access by triangle number? If I used something like:
random = rand(1)
if random <(1/4)
triangle1 = [50 0;0 50;-50 0]
elseif random>=(1/4) && random<(2/4)
...
Do you think that would fix the problem?
Walter Roberson
Walter Roberson il 25 Nov 2012
Consider going 3 dimensional. One dimension for x, one dimension for y, one dimension for triangle number.

Accedi per commentare.

Più risposte (0)

Categorie

Scopri di più su Creating and Concatenating Matrices in Help Center e File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by