Creating a vector field

43 visualizzazioni (ultimi 30 giorni)
Johannes
Johannes il 27 Nov 2012
Commentato: Nitin Phadkule il 9 Ott 2021
Hello everybody,
I am trying to create a vector field. The vector at each point is combined out of two others.
I tried
[x,y] = meshgrid(-2:.2:2,-2:.2:2) ; to create the points I want to take a look at
VectorX = [x./(2*pi*(x.^2+y.^2)),0]; is the Vector in the "x" direction
VectorY = [0,y./(2*pi*(x.^2+y.^2))]; is the Vector in the "y" direction
Vectortoplot = [(x./(2*pi*(x.^2+y.^2))),(y./(2*pi*(x.^2+y.^2)))];
quiver(x,y,Vectortoplot)
But all I get is an empty coordinat system form 0 to 1 in 0.1 steps in each direction. I am a little confused.
If you could help me, I would be very thankful.
  2 Commenti
Jan
Jan il 28 Nov 2012
Please learn how to format code in the forum. Inserting white lines does not look fancy.
Johannes
Johannes il 29 Nov 2012
I know, i am new in matlab, and this was the fastest way for me.
I will try to do that in the future, however i would be thankful for some help

Accedi per commentare.

Risposte (1)

Babak
Babak il 28 Nov 2012
Modificato: Babak il 28 Nov 2012
I don't know why you put a zero at the end of VectorX and a zero at the beginning of VectorY which makes those lines incorrect.
Your usage of quiver doesn't seem to be proper either. quiver needs 4 inputs. See
doc quiver
on that.
Here's what I ran:
[x,y] = meshgrid(-2:.2:2,-2:.2:2) ; %to create the points I want to take a look at
VectorX = [x./(2*pi*(x.^2+y.^2))]; %is the Vector in the "x" direction
VectorY = [y./(2*pi*(x.^2+y.^2))]; %is the Vector in the "y" direction
Vectortoplot = [(x./(2*pi*(x.^2+y.^2))),(y./(2*pi*(x.^2+y.^2)))];
% size(x)
% size(y)
% size(VectorX)
% size(VectorY)
quiver(x,y,VectorX,VectorY)
  3 Commenti
Rupchand Sutradhar
Rupchand Sutradhar il 5 Lug 2021
Modificato: Rupchand Sutradhar il 5 Lug 2021
how can I set the length of arrow ?
Nitin Phadkule
Nitin Phadkule il 9 Ott 2021
quiver(x,y,VectorX,VectorY,0)
add 0

Accedi per commentare.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by