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Azzera filtri

Help with the erfc function

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DEWDROP
DEWDROP il 17 Giu 2020
Commentato: Ameer Hamza il 18 Giu 2020
i am trying to use the ficks law which has erfc fuction and i am having trouble in defining the function.ERROR WHILE RUNNING THE ATTACHED CODE.THANK YOU IN ADVANCE!!!

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Ameer Hamza
Ameer Hamza il 17 Giu 2020
This is not a correct MATLAB syntax
erfc*(0.2/X3)
Function should be called like this
erfc(0.2/X3)
  2 Commenti
DEWDROP
DEWDROP il 18 Giu 2020
.thanks.....it works but it gives answer which is out of range .so the prooblem is with the error function or what ?i am confused.
Ameer Hamza
Ameer Hamza il 18 Giu 2020
I think this must be some other issues in the code. erfc() should be working fine.

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