no use of for loop
2 visualizzazioni (ultimi 30 giorni)
Mostra commenti meno recenti
Hi!
n=[0:0.01:0.5];
f=[2:0.01:3];
for k=1:length(n)
for l=1:length(f)
beta=n(k).*Dc/Dw
omega=2e9*pi*f(l);
epsilon=3./(1+j*omega*tau);
epsilon_k(k,l)=(beta*(epsilon)+(1-beta)(epsilon_cc));
end
end
is there any advice to programm this without using for loops?
Thank you
EDIT CORRECTED PROGRAM:
Hi sorry. here is the corrected program.
n=[0:0.01:0.5];
f=[2:0.01:3];
epsilon_cc=2
for k=1:length(n)
for l=1:length(f)
beta=n(k);
omega=2e9*pi*f(l);
epsilon=3./(1+j*omega*tau);
epsilon_k(k,l)=(beta*(epsilon)+(1-beta)*(epsilon_cc))
end
end
thank you for your help!
2 Commenti
Wayne King
il 29 Nov 2012
You should make your post so that people can actually execute your code. You do not give Dc, or Dw, and what is this line
epsilon_k(k,l)=(beta*(epsilon)+(1-beta)(epsilon_cc));
are you multiplying 1-beta and epsilon_cc?
Risposta accettata
Jan
il 29 Nov 2012
Modificato: Jan
il 29 Nov 2012
The variable "epsilon" does not change its value inside the loop, so move its calculation out of the loop.
"beta" does not change its value inside the inner loop, so move to the outer loop.
The variables "j", "epsilon_cc", "Dc" and "Dw" are not defined in the code snippet. We cannot guess their values or if they are functions.
The expression "(1-beta)(epsilon_cc)" is not valid in Matlab. Perhapos you forgot a "*".
Please cleanup the code at first.
0 Commenti
Più risposte (0)
Vedere anche
Categorie
Scopri di più su Loops and Conditional Statements in Help Center e File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!