Can anyone help me with this matlab code?
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Hello out there! I have a problem with following code. I have tre equations, which I have to find solutions to with help from newtons method in matlab. It's keep telling me, that I have a undefined variable.
function x = NEWT(x0,k)
x=x0;
for i=1:k
b=F(x);
s=DF(x)\b;
x=x-s;
end
end
function y = F(x)
y=zeros(3,1); % 0-punkter i 3x1 matrix - it is a vector
y(1)=2*x(1)^2-4*x(1)+x(2)^2+3*x(3)^2+6*x(3)+2;
y(2)=x(1)^2+x(2)^2-2*x(2)+2*x(3)^2-5;
y(3)=3*x(1)^2-12*x(1)+x(2)^2+3*x(3)^2+8;
end
function dy = DF(x)
dy=zeros(3,3);
dy(1,1)=4*x(1)-4;
dy(1,2)=2*x(2);
dy(1,3)=6*x(3)+6;
dy(2,1)=2*x(1);
dy(2,2)=2*x(2)-2;
dy(2,3)=4*x(3);
dy(3,1)=6*x(1)-12;
dy(3,2)=2*x(2);
dy(3,3)=6*x(3);
end
8 Commenti
Image Analyst
il 2 Dic 2012
How are you calling it? What values for x0 and k are you passing in?
Walter Roberson
il 2 Dic 2012
Which variable is being reported as undefined, and at which line?
Angelina
il 2 Dic 2012
Modificato: Image Analyst
il 2 Dic 2012
Image Analyst
il 2 Dic 2012
You can't do that. When it requires arguments you must first save your function then call it from the command line or another script or function and supply those arguments. You can't simply press the green run triangle button.
Angelina
il 2 Dic 2012
Image Analyst
il 2 Dic 2012
Edit and save your function by clicking on the disk icon. Then click in the command window panel. Type this (without the >> of course because that's just the MATLAB prompt):
>> NEWT(2, 3)
You can use different numbers than 2 and 3 - use whatever you think you should, I just used those as an example. It should report some errors. You fix those errors and repeat the above process until it runs to your satisfaction.
Angelina
il 2 Dic 2012
Image Analyst
il 2 Dic 2012
Of course. If you don't then there are still errors -- either errors in your logic and algorithm, or errors in the syntax.
Risposte (1)
Image Analyst
il 2 Dic 2012
0 voti
If you say NEWT(2,3) then x = 2, but in F(x) you say y(1)=2*x(1)^2-4*x(1)+x(2)^2+3*x(3)^2+6*x(3)+2 so then x must be an array, not a single number. What are your plans regarding that?
1 Commento
Angelina
il 2 Dic 2012
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