How can I make a for loop with two diferent indexes
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%My problem:
syms w;
for i=1:20
lam=i;
xi = fsolve(@(w) -tan(w/2) + w/2-(4./(lam))*(w/2).^3,[pi()-0.1 3*pi()-0.1]);
X(i) = xi(2)/pi()
end
%This is fine, but now I want to break the intervals in smaller ones:
syms w;
for i=1:0.2:20
lam=i;
xi = fsolve(@(w) -tan(w/2) + w/2-(4./(lam))*(w/2).^3,[pi()-0.1 3*pi()-0.1]);
X(i) = xi(2)/pi()
end
%And I want the values of xi(2)/pi() to be saved in a vector, but it want let me. I understand why, but I can't resolve it.
%Thank you very much to you all.
2 Commenti
Nasser M. Abbasi
il 6 Dic 2012
Modificato: Nasser M. Abbasi
il 6 Dic 2012
You are mixing syms with numerics. Decide what you want to do. Either use numerics or symbolic. Very confusing code. Why calling fsolve() with syms?
But in order to make a symbolic vector, do
range=1:0.2:20;
X = sym(zeros(1, length(range)));
Risposta accettata
Matt Fig
il 6 Dic 2012
Modificato: Matt Fig
il 6 Dic 2012
syms w;
cnt = 1:.2:20;
for ii=1:length(cnt)
xi = fsolve(@(w) -tan(w/2) + w/2-4/ii*(w/2).^3,[1 3]*pi-.1);
X(ii) = xi(2)/pi;
end
4 Commenti
Matt Fig
il 6 Dic 2012
Nuno, did you run the code? It does exactly what you describe. You want to solve the equation for every value of lam in 1:.2:20 and store the second solution in a vector X. That is what the code does....
Nasser, True enough! I just copied Nuno's code and made the minimal changes.
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