Info

Questa domanda è chiusa. Riaprila per modificarla o per rispondere.

for loop for t

4 visualizzazioni (ultimi 30 giorni)
Ali
Ali il 7 Lug 2020
Chiuso: MATLAB Answer Bot il 20 Ago 2021
t=0.75
a1=2*t*x/(1+t)+t+k;
ad=t/a1;
ap=k/a1;
p(1)=1.01325*10^5;
for i=1:14;
p(i+1)=p(i)+20000;
end
sd=(Ad*p)/(2*rho*g*Veo);
sp=(Ap*p)/(2*rho*g*Vco);
kdd=sd*(ad-q*keb);
kdp=sd*ap;
kpp=sd*o*(q*kcb+ap);
kpd=sd*o*ad;
B=[1];
B(1:15)=B;
C=2*(rw*ep+ed);
C(1:15)=C;
D=(1-kdd)+(rw^2+kpp)+4*rw*ep*ed;
E=2*ed*(rw^2+kpp)+rw*ep*(1-kdd);
F=(rw^2+kpp).*(1-kdd)+kpd.*kdp;
B=B';
C=C';
D=D';
E=E';
F=F';
w=[B C D E F];
[m,n] = size(w) ;
r = zeros(m,n-1) ;
for i = 1:m
r(i,:)= roots(w(i,:))
end
r=real(r)
r=unique(r)
  4 Commenti
Aquatris
Aquatris il 7 Lug 2020
what is the question?
Image Analyst
Image Analyst il 7 Lug 2020
No question, just an announcement.
I tried to run it but after entering random numbers for lots of missing variables, I finally gave up. It's pretty clear that Ali never read the links Rik sent.

Risposte (0)

Questa domanda è chiusa.

Tag

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by