Proportion of Failures Test
    3 visualizzazioni (ultimi 30 giorni)
  
       Mostra commenti meno recenti
    
I was reading the following website:
It states:
The result of the test is to accept if
PValuePOF<F(TestLevel)
Should this actually be 
F(LR_POF)<F(TestLevel)
For example, I calculated the following in excel: 
  Table 3  POF
  LR_POF        0.0168 = =-2*((251-13)*LN((251*(1-0.05))/(251-13))+13*LN((251*0.05)/13))
  F(LR_POF)     0.1031 =1-CHIDIST(LR_POF,1)
  PValuePOF     0.8969 =1-F_LR_POF
  F(TestLevel)  0.6703 =1-CHIDIST(0.95,1)
  Result  accept =IF(F_LR_POF<F_TestLevel,"accept","reject")
I look forward to your response.
Kindest Regards,
Clarissa                                                          
0 Commenti
Risposte (0)
Vedere anche
Categorie
				Scopri di più su Risk Management Toolbox in Help Center e File Exchange
			
	Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
