How to plot minima and maxima of two matrices

2 visualizzazioni (ultimi 30 giorni)
Hello
It was supposed the following lines find the maximum of the rows in RAJ_Mx1 taking into consideration only those values where the corresponding elements in RHMORx are greater and less than zero. When I plot RAJ_Mx1 and RHMORx together, I cannot find these values! Would you please assist me to find out why and how can I plot them properly to find the maxima that the program was supposed to provide with?
peakMOM_pos_R_Ank_pos_powerIny=mean(max(RAJ_In1.*(RAJMORy>0 ),[],2));
peakMOM_pos_R_Ank_neg_powerIny=mean(min(RAJ_In1.*(RAJMORy>0 ),[],2));
peakMOM_neg_R_Ank_pos_powerIny=mean(max(RAJ_In1.*(RAJMORy<0 ),[],2));
peakMOM_neg_R_Ank_neg_powerIny=mean(min(RAJ_In1.*(RAJMORy<0 ),[],2));
Thank you so much,

Risposta accettata

Cris LaPierre
Cris LaPierre il 12 Ago 2020
Modificato: Cris LaPierre il 12 Ago 2020
The four lines of code you shared each check a different condition.
  1. max value in each row of RAH_In1 but only considering values that correspond to positive values in RAJMORy.
  2. min value in each row of RAH_In1 but only considering values that correspond to positive values in RAJMORy.
  3. max value in each row of RAH_In1 but only considering values that correspond to negative values in RAJMORy.
  4. min value in each row of RAH_In1 but only considering values that correspond to negative values in RAJMORy.
Having found the corresponding value for each of the 9 rows, the last thing each line of code does is calculate the mean of the 9 values. The result is a single number. Because it is a mean, you will not find a corresponding value in either matrix.
peakMOM_pos_R_Ank_pos_powerIny = mean(max(RAJ_In1.*(RAJMORy>0),[],2));
  1 Commento
Vahid Esmaeili
Vahid Esmaeili il 13 Ago 2020
Dear Cris,
Thank you so much for your answer. I did not pay enough attention!
Vahid,

Accedi per commentare.

Più risposte (0)

Categorie

Scopri di più su Data Distribution Plots in Help Center e File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by