fastest way to apply A\B on each matrix page

1 visualizzazione (ultimi 30 giorni)
I would like to find an efficient fast way for calculating:
for i = 1:n
X(:,:,i) = A(:,:,i)\B(:,:,i)
end
where A and B are 10*10*n, and 10*1*n size matrices respectively. the matrices are large and must be called meny times. therefore I was thinking of replacing "for loops" with a faster way that does it very fast and not iteratively.

Risposta accettata

Bruno Luong
Bruno Luong il 17 Ago 2020
Modificato: Bruno Luong il 17 Ago 2020
Why insist on ARRAYFUN, your for-loop is perfectly fine. ARRAYFUN is a "vectoriztion" scam.
n = 100;
A = rand(10,10,n);
B = rand(10,1,n);
X = arrayfun(@(p) A(:,:,p)\B(:,:,p), 1:n, 'unif', 0);
X = cat(3,X{:});
  5 Commenti
hosein Javan
hosein Javan il 17 Ago 2020
Bruno Luong. sorry for misunderstanding. I did not mean to decieve. I only thought that arrayfun is a best replace for "loop". I'll edit the question.
hosein Javan
hosein Javan il 17 Ago 2020
I studied your MultiSolver. it was using concatenation diagonally and make a sparse matrix as I said. I see there's no better way. however ur using of repmat and rehsape was something speedy to extract unknowns without loops. I accept your answer. thanks, but I'd like to mention once more that it was misunderstanding. please don't use words like "big scam". thanks again.

Accedi per commentare.

Più risposte (0)

Categorie

Scopri di più su Operating on Diagonal Matrices in Help Center e File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by