I want to write a recursive Function that can calculate the sum of all the digit. If the input is 12345 then the answer will be 1+2+3+4+5 , without using string2num and loop.
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function output= digit_sum(n)
if n<10
output=fix(n);
end
if n>0
output=output+digit_sum(n*0.1);
end
end
I wrote this code but the problem I am facing is if i set output=0; anywhere then in all the recalling function process my result will turn to be 0, How to Solve this ?
4 Commenti
James Tursa
il 17 Ago 2020
Modificato: James Tursa
il 17 Ago 2020
Maybe you should take a step back and write down the algorithm on paper using words instead of code. Then take a simple 2 digit example and run it through your algorithm on paper. Once you have things figured out for your algorithm, then turn it into code and start testing. That will force you to understand the algorithm first, before you even get to the coding stage.
Risposta accettata
David Hill
il 17 Ago 2020
function output= digit_sum(n,a)
if nargin==1
a=0;
end
if n<10
output=a+fix(n);
else
output=digit_sum(floor(n*.1),a+mod(n,10));
end
end
3 Commenti
David Hill
il 17 Ago 2020
Using nargin, your function can have 1 or more inputs.
output = digit_sum(12345);
Try the above on my function.
Più risposte (7)
Saptarshi Neogi
il 30 Ago 2020
You can do this with any inbuit functions.
function x = digit_sum(n)
x=0;
if n>0
x=mod(n,10)+digit_sum(floor(n./10));%recursive
end
0 Commenti
Sanjay Raju
il 13 Set 2020
function x=digit_sum(inp)
if inp<10
x=inp;
else
x = mod(inp,10) + digit_sum(fix(inp/10));
end
end
0 Commenti
Farhath Surayya
il 19 Nov 2020
function output= digit_sum(n) if n<10 output=fix(n); end if n>0 output=output+digit_sum(n*0.1); end end
0 Commenti
Ramesh Patel
il 22 Lug 2021
function sum = digit_sum(num)
if fix(num)==0
sum=0;
else
x = fix(num/10);
sum = rem(num,10) + digit_sum(x);
end
end
%is this code correct.output is right but i am not able to understand when
%if fix(num)==0 condition will true than value of sum should be zero. but
% zero is not output ,why?
0 Commenti
Ans sadiq
il 19 Ago 2021
function out=digit_sum(in)
q=in;
a=q/10;
b=floor(a);
c=q-b*10;
w=c;
if q>0
w=w+digit_sum(b);
end
out=w;
end
0 Commenti
Selman Baysal
il 5 Gen 2022
Hi, i have just done this homework. Here is my code:
function output = digit_sum(A)
remA = rem(A,10); % calculates the last digit of A
if isequal(A,0)
output = 0;
else
A = (A-rem(A,10))/10; % gives the new A with substracting the last digit
output = remA + digit_sum(A);
end
end
0 Commenti
youssef
il 25 Ott 2023
function x=digit_sum(n)
x=0;
if n<=0
x=0;
else
x=x+mod(n,10)+digit_sum((n-mod(n,10))/10);
end
end
0 Commenti
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