Received Power Vs Distance

1 visualizzazione (ultimi 30 giorni)
A.J.M
A.J.M il 2 Set 2020
Commentato: A.J.M il 3 Set 2020
Hi Everyone;
My MATLAB code result in the received power increases with distance as shown in the figure in spite I use Friis formula. Where is my mistake.
Pr=Pt*Gt*Gr*lambda^2./16*pi^2.*(Z).^2; %Friis Formula

Risposta accettata

Alan Stevens
Alan Stevens il 3 Set 2020
If Z is distance then you should probably have
Pr=Pt*Gt*Gr*lambda^2./(16*pi^2.*Z.^2);
Note the position of the parentheses. In your version Z is on the numerator.
  3 Commenti
Alan Stevens
Alan Stevens il 3 Set 2020
Yes, the problem was the positioning of the parentheses.
I've no idea if the formula is correct in total, but power almost certainly decreases with distance away from the source.
A.J.M
A.J.M il 3 Set 2020
Thanks a lot Mr.Alan Stevens.

Accedi per commentare.

Più risposte (0)

Categorie

Scopri di più su Programming in Help Center e File Exchange

Tag

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by