I have to make a matrix with 100 columns and 100 rows, I have to assign "2" to all even columns and "0" to odd columns

Hi, I have to make a matrix with 100 columns and 100 rows, I have to assign "2" to all even columns and "0" to uneven columns. I also have to use for loops.

I've made this so far:

z = zeros(100);
[m , n ] = size(A)
for i=1:100
    if mod(i,2)==0
        z(:,i) = 2
    end
end

But it creates for than 100 columns and rows and won's stop running, if I try to stop it, it opens up a new file named Workspacelistener.

What could I be doing wrong?

[KSSV]

There is a typo error in your code, while getting sizes m,n you used A. Okay that m,n are not used next. You are taking output z(:,i) = 2 every time in a loop. This takes hell lot of time. You need to terminate the output with ;.

z = zeros(100);
[m , n ] = size(z)
for i=1:100
    if mod(i,2)==0
        z(:,i) = 2 ;   % <------ terminate the output 
    end
end

You need not to use loop to acieve this. Check the answer.

Answer 1

[KSSV]

A = zeros(100) ;
A(:,2:2:end) = 2 ;