Creating a matrix using diag

Hi,
Would you please help me to write a script with "diag" command to create the matrix as shown in image. http://s1.postimage.org/5i4gd1esv/matrix.jpg By they way, it's a 99 X 99 matrix.
Thank you, John

2 Commenti

Matt J
Matt J il 27 Gen 2013
Modificato: Matt J il 27 Gen 2013
The toeplitz() command would be quicker.
John Edward
John Edward il 27 Gen 2013
Thanks for your reply and I forgot to mention that it's a 99 by 99 matrix. Can you be able to script it for me.
Thank you, John

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 Risposta accettata

Matt J
Matt J il 27 Gen 2013
>> z=zeros(3,1); z(1)=2; z(2)=-1; A=toeplitz(z)
A =
2 -1 0
-1 2 -1
0 -1 2

3 Commenti

John Edward
John Edward il 27 Gen 2013
Matt, how would you make it a 99 X 99 matrix. That's where I am stock. Thx man.
Cedric
Cedric il 27 Gen 2013
Modificato: Cedric il 27 Gen 2013
Look at what happens if you replace the 3 in Matt's answer with e.g. 5.
But just to be sure, you want a tri-diagonal 99x99 matrix, right?
John Edward
John Edward il 27 Gen 2013
Thank YOU, YOU are a life saver. It worked.

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Più risposte (2)

diag(this, -1) + diag(that) + diag(theother,1)

1 Commento

John Edward
John Edward il 27 Gen 2013
Thanks for your reply but it's a 99 by 99 matrix.

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Matt J
Matt J il 27 Gen 2013
Modificato: Matt J il 27 Gen 2013
A small example
>> A=diag([1,1,1])-diag([1,1],1); A=A+A.'
A =
2 -1 0
-1 2 -1
0 -1 2

4 Commenti

John Edward
John Edward il 27 Gen 2013
Thanks for your reply but it's a 99 by 99 matrix. How would you script that? Thx a lot.
Matt J
Matt J il 27 Gen 2013
If you understood how it works for 3x3, it should be pretty obvious how to extend it to the 99x99 case.
John Edward
John Edward il 27 Gen 2013
Honestly, I am new to matlab and I have been working on this for past 4 hours and I can't get the code right. Can you help me on that? Thank you.
I don't know what more help I can give without just doing the whole thing for you. Are you aware that
>> help diag
or
>> doc diag
will display an explanation of the diag command? If you've read that documentation, it should be really easy. Some more examples:
>> diag([1 2 3 4]), diag([10 20 30], 2), diag([5 7 6],-1)
ans =
1 0 0 0
0 2 0 0
0 0 3 0
0 0 0 4
ans =
0 0 10 0 0
0 0 0 20 0
0 0 0 0 30
0 0 0 0 0
0 0 0 0 0
ans =
0 0 0 0
5 0 0 0
0 7 0 0
0 0 6 0

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