Do not take any amount

1 visualizzazione (ultimi 30 giorni)
lech king
lech king il 5 Ott 2020
Commentato: lech king il 5 Ott 2020
pop=randi([100],20,8);
[r1,c1]=size(pop);
for i=1:r1
A=randi(100);
if A<=90
pool(i,:)=pop(i,:);
end
end
Hi
I want if the condition is not met, the pool variable does not take any value, in other words, in the end, for example, it becomes an 18x8 matrix, not an 20x8 matrix with 2 rows containing the value 0
Thank you for your guidance

Risposta accettata

KSSV
KSSV il 5 Ott 2020
Modificato: KSSV il 5 Ott 2020
pop=randi([100],20,8);
[r1,c1]=size(pop);
pool = zeros([],c1) ;
count = 0 ;
for i=1:r1
A=randi(100);
if A<=90
count = count+1 ;
pool(count,:)=pop(i,:);
end
end
You need not to use loop...it can be vectorized.
pop=randi([100],20,8);
[r1,c1]=size(pop);
A = randi(100,1,r1) ;
pool = pop(A<=90,:) ;

Più risposte (0)

Categorie

Scopri di più su Mathematics in Help Center e File Exchange

Prodotti


Release

R2019b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by