Azzera filtri
Azzera filtri

Do not take any amount

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lech king
lech king il 5 Ott 2020
Commentato: lech king il 5 Ott 2020
pop=randi([100],20,8);
[r1,c1]=size(pop);
for i=1:r1
A=randi(100);
if A<=90
pool(i,:)=pop(i,:);
end
end
Hi
I want if the condition is not met, the pool variable does not take any value, in other words, in the end, for example, it becomes an 18x8 matrix, not an 20x8 matrix with 2 rows containing the value 0
Thank you for your guidance

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KSSV
KSSV il 5 Ott 2020
Modificato: KSSV il 5 Ott 2020
pop=randi([100],20,8);
[r1,c1]=size(pop);
pool = zeros([],c1) ;
count = 0 ;
for i=1:r1
A=randi(100);
if A<=90
count = count+1 ;
pool(count,:)=pop(i,:);
end
end
You need not to use loop...it can be vectorized.
pop=randi([100],20,8);
[r1,c1]=size(pop);
A = randi(100,1,r1) ;
pool = pop(A<=90,:) ;

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