Creating an array of dependent symbolic variable

22 views (last 30 days)
I need to create 'N' equations based on user input 'N' which is a natural number.
Each equation is supposed to have a variable A which is a dependent on x. This 'A' term is different for each equation. Equation1 will have A1, equation2 will have A2 and so on.
I am creating this term using the expresion below.
A = sym('A', [1 N]);
This gives me symbolic variables A1, A2, A3... AN. But the problem is these terms are just symbolic variables and not dependent on x. So if I differentiate the equation with respect to x, these terms dissappear. If I use A(x) to create the variable (like a normal dependent variable), it returns a 1x1 symbolic function instead of 1xN symbolic variables.
A(x) = sym('A', [1 N]);
The above equation creates 1xN symbolic variables but the output is of type 1x1 symbolic function. Is there a way to isolate each term from this function or is there any other way to create a dependent variable array.
Gekkouga on 13 Oct 2020
I have 'N' sections and each section has an equation.
The equations have some common terms and different terms which depend on the boundary conditions. I am creating those equations through a loop and conditional statements which will be solved later. So, I need the variable 'A' to be an array so that I can add it to the equations while iterating through the loop.

Sign in to comment.

Accepted Answer

madhan ravi
madhan ravi on 13 Oct 2020
Edited: madhan ravi on 13 Oct 2020
A(x) = str2sym(regexprep(char(A), '(\_?\d)+', '$0(x)'))
Gekkouga on 14 Oct 2020
Thanks. It worked.
Sorry to put you through that.

Sign in to comment.

More Answers (1)

Steven Lord
Steven Lord on 13 Oct 2020
syms A [1 2]
eq1 = A(1)+2*A(2) == 42
eq2 = 3*A(1)-4*A(2) == 99
S = solve(eq1, eq2)
A1 = S.A1
A2 = S.A2
  1 Comment
Gekkouga on 13 Oct 2020
I think you didn't get my question.
I need to create an array of dependent symbolic varaible, not just symbolic variables. Something like
A = [A1(x) A2(x) A3(x)]

Sign in to comment.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by