sbit stream

w= 1 0 1
w= 0 1 1
w= 0 1 0
how came this can be written in straight line
w= 1 0 1 0 1 1 0 1 0

 Risposta accettata

Walter Roberson
Walter Roberson il 24 Apr 2011

0 voti

You might find this easier to understand:
w = []; for i = 1:30 w = [w, A(i), B(i), C(i)]; end

2 Commenti

Oleg Komarov
Oleg Komarov il 24 Apr 2011
Seriously :)?
Walter Roberson
Walter Roberson il 24 Apr 2011
Yup. Get it working first, and *then* optimize it.

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Più risposte (1)

Walter Roberson
Walter Roberson il 24 Apr 2011

0 voti

It cannot. The first one assigns the row vector [0 1 0] to w, but the second one assigns a row vector of length 9 to w.
If your original data is a 3 x 3 matrix instead, then
w = reshape(w.',1,numel(w));

7 Commenti

mahaveer hanuman
mahaveer hanuman il 24 Apr 2011
not working
mahaveer hanuman
mahaveer hanuman il 24 Apr 2011
those 'w' are vectors
Walter Roberson
Walter Roberson il 24 Apr 2011
What *exactly* do you have for input? And what *exactly* do you want for output?
w = 1 0 1
is not valid MATLAB input.
mahaveer hanuman
mahaveer hanuman il 24 Apr 2011
for i=1:30;
w=([A(i),B(i),Q(i)]);
end
after perfoming this
i got out put as
w=
1 0 1
w=
0 0 1
w=
1 1 1
and so on.........................
now i need to make them into one single bit stream
like
w=1 0 1 0 0 1 1 1 1 .....................
Oleg Komarov
Oleg Komarov il 24 Apr 2011
Preallocate before the loop:
w = zeros(1,30*3);
for ...
w(i*3-2:i*3) = ([A(i),B(i),Q(i)]);
end
Walter Roberson
Walter Roberson il 24 Apr 2011
N = 30;
w = reshape([reshape(A(1:N),1,N); reshape(B(1:N),1,N); reshape(C(1:N),1,N)], 1, 3*N);
The above does not assume that A, B, or C are row vectors or column vectors. If the shapes are known and consistent, the code can be simplified -- especially if you are putting together _all_ of the vector instead of just a subset of it.
For example, if they are all row vectors and you are using all of them, then
w = [A;B;C]; w = w(:).';
mahaveer hanuman
mahaveer hanuman il 24 Apr 2011
thanks its working

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