Azzera filtri
Azzera filtri

How to make a loop through each row?

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Daria Ivanchenko
Daria Ivanchenko il 21 Ott 2020
Commentato: David Hill il 21 Ott 2020
Hi! I have a variable A in the size of 50x15000 with different numbers. And I have variable B, the same size 50x15000, that has only zeros and ones. I want to filter the data in the variable A based on variable B, and put the result in variable C. I need to take the numbers from A only if it is zero in the matrix B. One row is one trial in both A and B.
I wrote a small for loop:
C = NaN(size(A));
for i = 1:size(A,1)
C(i,:) = A(i, B(i,:) == 0);
end
The problem is that, after filtering the data, each row has different number of columns, so it doesn't want to be in one matrix. I have a message like this: "Unable to perform assignment because the size of the left side is 1-by-15000 and the size of the right side is 1-by-13683".
How can I solve this problem?
Thank you!
  2 Commenti
Stephen23
Stephen23 il 21 Ott 2020
"How can I solve this problem?"
Which would you prefer?:
  • a matrix padded with NaN (or some other value).
  • a container array (e.g. cell array) of vectors.
Daria Ivanchenko
Daria Ivanchenko il 21 Ott 2020
A matrix padded with NaN would be better!

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Risposte (1)

David Hill
David Hill il 21 Ott 2020
Modificato: David Hill il 21 Ott 2020
Make C a cell array
for i = 1:size(A,1)
C{i} = A(i, B(i,:) == 0);
end
  2 Commenti
Daria Ivanchenko
Daria Ivanchenko il 21 Ott 2020
Yes, this works, thanks, but it is really necessary for me to have all in one matrix and not in differents cells.
David Hill
David Hill il 21 Ott 2020
C=zeros(size(A));
C(B==0)=A(B==0);
C(B==1)=nan;

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