Info
Questa domanda è chiusa. Riaprila per modificarla o per rispondere.
Am I correct in my approach regarding interpolation?
1 visualizzazione (ultimi 30 giorni)
Mostra commenti meno recenti
Dear all
I have the vector
A={
[ NaN]
[ NaN]
[1.0877]
[1.0909]
[ NaN]
[ NaN]
[ NaN]
[ NaN]
[ NaN]
[ NaN]
[ NaN]
[ NaN]
[ NaN]
[ NaN]
[ NaN]
[ NaN]
[ NaN]
[ NaN]
};
and the date vector
D={'10/2008'
'11/2008'
'12/2008'
'1/2009'
'2/2009'
'3/2009'
'4/2009'
'5/2009'
'6/2009'
'7/2009'
'8/2009'
'9/2009'
'10/2009'
'11/2009'
'12/2009'
'1/2010'
'2/2010'
'3/2010'
'4/2010'
'5/2010'
'6/2010'
'7/2010'
'8/2010'
'9/2010'
'10/2010'
'11/2010'
'12/2010'
'1/2011'
'2/2011'
'3/2011'
'4/2011'
'5/2011'
'6/2011'
'7/2011'
'8/2011'
'9/2011'
};
and I am doing interpolation
xi = datenum(D, 'mm/yyyy');
z = interp1(xi(1:2:end),cell2mat(A(:,1)),xi);
Equivalently,
idx = ~isnan(cell2mat(A(:,1)));
z= interp1(xi(idx),cell2mat(A(idx,1)),xi);
Could you please verify that I am correct in my approach ?
thanks
0 Commenti
Risposte (1)
Azzi Abdelmalek
il 14 Feb 2013
v=cell2mat(A)
xi = datenum(D, 'mm/yyyy');
z = interp1(xi(3:4),v(3:4),xi,'spline');
2 Commenti
Satyam Gaba
il 24 Ago 2018
No it's not a linear function. Spline interpolation can be used for polynomial interpolation for low degree polynomials as well as higher degrees.
Questa domanda è chiusa.
Vedere anche
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!