x(t) = Λ(t/4)[Π((​t+4)/6)+Π(​(t-4)/6)]+​Λ(t), t = [-10,10]

Hi,

I am new in MatLab and I am having some trouble plotting the above x(t)using the rectpuls and i'm not sure where i am going wrong. By default the code must be like that:

step = 0.01;
t =


xt = 
figure(1)

I tried the below code but something is wrong with the tripuls's arguments.[Ihave seen that it's form is tripuls(t,w,s), where w is the width where here is 0.25? and s is the skew, where here is ...?]. In the paper I have found that: Π((t+4)/6)+Π((t-4)/6) = Π(t/6+4/6)+Π(t/6-4/6) = Π(t/(2*3)) + Π(4/6) + Π(t/(2*3) - Π(4/6) =[ Π(4/6) = 0]=u(t+3) - u(t-3) - u(t+3) + u(t-3) = 0. So finally x(t) = Λ(t), but what about the code?

step = 0.01;
t = -10:step:10;

syms t
xt = tripuls(t,0,1)*((heaviside((t+4)/6)+heaviside((t-4)/6)))+ tripuls(t);
figure(1)
fplot(t,xt);

[Walter Roberson]

Caution: you should use

sympref('heavsideatorigin', 1)

if you are using unit step function.

[milton]

Thank you, Walter Roberson for the immidiate response but since I'm in the beginning I haven't learnt yet the sympref(). Is there any simpler way to manage that issue?

[Debasish Samal]

Hi,

The 'tripuls' function accepts input arguments of type 'single' or 'double' but it is 'symbolic' in this case. Can you try using these data types instead?

If you want to plot unit step function without 'Heaviside', an example can be found in the following MATLAB Answer:

https://www.mathworks.com/matlabcentral/answers/323383-plotting-a-unit-step-function-without-heaviside

-Debasish

[milton]

Thank you, Debasish Samal! It was really helpful the MATLAB Answer that you post!