Contrast stretching transformation in Image Processing

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I tried to solve for question but i didn't do.
I tried this code for solving.
p1=[0,0];
p2=[75,5];
p3=[140,250];
p4=[255,255];
m1=(p1(1,2)-p2(1,2))/(p1(1,1)-p2(1,1));
m2=(p2(1,2)-p3(1,2))/(p2(1,1)-p3(1,1));
m3=(p3(1,2)-p4(1,2))/(p3(1,1)-p4(1,1));
c1=p1(1,2)-m1*p1(1,1);
c2=p2(1,2)-m2*p2(1,1);
c3=p3(1,2)-m3*p3(1,1);
%% Transformation function
t=[];
for x=0:255
if(x<=p2(1,1))
t=[t (m1*x+c1)];
end
if(x>p2(1,1) && x<=p3(1,1))
t=[t (m2*x+c2)];
end
if(x>p3(1,1) && x<=p4(1,1))
t=[t (m3*x+c3)];
end
end
for n=1:s(1,1)
for m=1:s(1,2)
ot(n,m)=t(a(n,m)+1);
end
end
I don't know how to find answer of this question. I will be glad if you help.
  1 Commento
Rooter Boy
Rooter Boy il 15 Nov 2020
I found answer is 130 but i'm not sure.
I tried this:
r = input("Please input the intensity value, r: ");
fprintf("\n");
r1 = 70;
r2 = 150;
s1 = 30;
s2 = 230;
Point_1 = [0 0];
Point_2 = [r1 s1];
Point_3 = [r2 s2];
Point_4 = [255 255];
x = 1;
y = 2;
%Slope of region 1%
Rise = Point_2(y) - Point_1(y);
Run = Point_2(x) - Point_1(x);
Slope_1 = Rise/Run;
%Slope of region 2%
Rise = Point_3(y) - Point_2(y);
Run = Point_3(x) - Point_2(x);
Slope_2 = Rise/Run;
%Slope of region 3%
Rise = Point_4(y) - Point_3(y);
Run = Point_4(x) - Point_3(x);
Slope_3 = Rise/Run;
if r <= r1
fprintf("Region 1\n");
s = Slope_1*r;
fprintf("The output intensity, s = T(r) is: %.2f\n",s);
elseif (r1 < r) && (r < r2)
fprintf("Region 2\n");
Constant_Offset = s1;
Relative_Run = (r - r1);
s = Slope_2*Relative_Run + Constant_Offset;
fprintf("The output intensity, s = T(r) is: %.2f\n",s);
elseif r >= r2
fprintf("Region 3\n");
Constant_Offset = s2;
Relative_Run = (r - r2);
s = Slope_3*Relative_Run + Constant_Offset;
fprintf("The output intensity, s = T(r) is: %.2f\n",s);
end

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Image Analyst
Image Analyst il 16 Nov 2020
Wow. Try this much easier way:
r = [70, 150]
s = [30, 230];
output = interp1(r, s, 110) % output is 130.
  4 Commenti
Image Analyst
Image Analyst il 17 Nov 2020
If this solved the question, can you "Accept this answer" unless you want to wait for possible other, better answers.
Rooter Boy
Rooter Boy il 17 Nov 2020
Excuse me,
Sir, i accepted your answer.
I sometimes forget it.

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