How can I modify negative values from two datasets based on a positive given one?

1 visualizzazione (ultimi 30 giorni)
Hi. I need some help.
I wrote this code to fix two datas(First_data,Second_data) based on another one(Third_data). The datasets have the same trend, so the graph should look similar(not identic).
The code looks that it works when the values are positive but not on negative ones.
DateO={'20-Apr-2020 12:06:00','20-Apr-2020 12:07:00','20-Apr-2020 12:08:00','20-Apr-2020 12:09:00','20-Apr-2020 12:10:00','20-Apr-2020 12:11:00','20-Apr-2020 12:12:00','20-Apr-2020 12:13:00'};
DateT={'20-Apr-2020 12:06:00','20-Apr-2020 12:07:00','20-Apr-2020 12:08:00','20-Apr-2020 12:09:00','20-Apr-2020 12:10:00','20-Apr-2020 12:11:00','20-Apr-2020 12:12:00','20-Apr-2020 12:13:00'};
DateTh={'20-Apr-2020 12:06:30','20-Apr-2020 12:07:30','20-Apr-2020 12:08:30','20-Apr-2020 12:09:30','20-Apr-2020 12:10:30','20-Apr-2020 12:11:30','20-Apr-2020 12:12:30','20-Apr-2020 12:13:30'}; % Picarro
A = datetime(DateO,'InputFormat','dd-MM-yyyy HH:mm:ss');
B = datetime(DateT,'InputFormat','dd-MM-yyyy HH:mm:ss');
C = datetime(DateTh,'InputFormat','dd-MM-yyyy HH:mm:ss');
First_data=[-216,-220,-225,-232,-233,-233,-244,-246];
Second_data=[89,66,30,7,9.6,-5.8,-12,-16];
Third_data=[7.59,3.52,3.8,3.21,2,3.42,2.3,4.36];
figure;
left={Third_data,Third_data};
right={First_data,Second_data};
right_time = {A, B};
xlab=["Third data"," Third data"];
ylab=["First data","Second data"];
for i=1:length(left)
x = left{i};
y = right{i};
t = right_time{i};
if i == 1
Coeff(i) = max(y)/max(x);
else
Coeff(i) = max(x)/max(y);
end
y(y>0) = y(y>0).*Coeff(i);
y(y<0) = y(y<0).*Coeff(i);
Clb_values{i} = y;
Clb = Clb_values{i};
subplot(2,1,1*i);
yyaxis left;
plot(C, x);
ylabel('Third_data')
yyaxis right;
plot(t,Clb);
ylabel(ylab(i))
end
Clb_1=Clb_values{1,1};
Clb_2=Clb_values{1,2};
Thank you
  5 Commenti

Accedi per commentare.

Risposte (1)

Nora Khaled
Nora Khaled il 20 Nov 2020
maybe this works ?
if i == 1
y=y+(x-y);
Coeff(i) = abs(max(y)/max(x));
else
Coeff(i) = abs(max(x)/max(y));
end
  1 Commento
Kofial
Kofial il 20 Nov 2020
I tried this and the "First data" becomes identic with the "Third data". This means that something is still wrong. Should be something to do with the coffee...

Accedi per commentare.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by