how to calculate number of unique element in array?
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Putri Basenda Tarigan
il 22 Nov 2020
Commentato: Putri Basenda Tarigan
il 22 Nov 2020
Hi all.
if I have matrix like:
c =
1 1
1 1
1 1
2 1
2 2
2 3
2 4
2 5
2 5
3 1
3 1
3 2
how can I calculate number of unique element in column 2 according to column 1?
for the above matrix, the result should be:
1 1
2 5
3 2
Thanks in advance
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Ameer Hamza
il 22 Nov 2020
Modificato: Ameer Hamza
il 22 Nov 2020
Try splitapply()
c = [
1 1
1 1
1 1
2 1
2 2
2 3
2 4
2 5
2 5
3 1
3 1
3 2]
out = [unique(c(:,1)) ...
splitapply(@(x) numel(unique(x)), c(:,2), c(:,1))]
or accumarray():
out = [unique(c(:,1)) ...
accumarray(c(:,1), c(:,2), [], @(x) numel(unique(x)))];
And if the second column also contain all positive integers in increasing order then you can just try
out = [unique(c(:,1)) ...
splitapply(@max, c(:,2), c(:,1))]
%
out = [unique(c(:,1)) ...
accumarray(c(:,1), c(:,2), [], @max)];
Più risposte (1)
Bruno Luong
il 22 Nov 2020
Modificato: Bruno Luong
il 22 Nov 2020
c =[
1 1
1 1
1 1
2 1
2 2
2 3
2 4
2 5
2 5
3 1
3 1
3 2 ]
d=unique(c,'rows');
c1=d(:,1);
i=find([true; diff(c1)~=0; true]);
count=diff(i);
c1=c1(i(1:end-1));
t=table(c1,count)
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