Square Root Complex Numbers
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Hi
I'm new to Matlab. I have a matrix of data for example 1.04,-5.84,-5.84,8.54 etc. As you can see its a mixture of positive and negative values. I have to square root all the numbers and then add the square root up.
I get an output like this: 0 + 0.2572i 1.4758 0 + 1.0258i 0 + 1.0297i .... etc
How can I add these up because when I do the sum total is displayed like so: 24.1589 +25.8258i I was expecting a real number such as 25.0414 why is it formatted like this. I am new to matlab so not sure what I need to do, works fine if my data has no negative numbers so I assume it's to do with that.
Thanks
3 Commenti
Walter Roberson
il 9 Mar 2013
Suppose your entire data was just (say) -2 . Then what would you want as the result of the operation?
Josh
il 9 Mar 2013
Youssef Khmou
il 9 Mar 2013
real parts are summed separately from imaginary parts , if you want add both Real and Imag sumsthen try :
r=rand(10);
p=sqrt(r);
S=sum(real(p(:)))+sum(imag(p(:)));
Risposte (2)
Youssef Khmou
il 9 Mar 2013
hi Josh,
the square root of <0 number is complex number , if you only want the real part use "real" function, but if you want imaginary part, use "imag" function, and for the modulus you can use "abs" function , example :
r=randn(10);
p=sqrt(r);
Real_part=sum(real(p(:)));
Imag_part=sum(imag(p(:)));
Modul_part=sum(abs(p(:)));
Walter Roberson
il 10 Mar 2013
Modificato: Walter Roberson
il 10 Mar 2013
To get the results you indicate you want (which are not the results one would normally want when taking the square roots of negative numbers),
sum(sqrt(r(r>0))) - sum(sqrt(-r(r<0)))
Remember, sqrt(-A) is not -sqrt(A) but is instead 1i * sqrt(A) where 1i indicates sqrt(-1)
5 Commenti
Yogan Sganzerla
il 6 Ago 2019
Dear Walter,
I have a matrix M with complex number, as u can see the image below.

I would like to know the correct way to extract the squere root of M.
Could I use sqrm(M)?
Thank you for your attention.
Torsten
il 6 Ago 2019
You want to get the matrix A with A^2 = M or with A.^2 = M ?
Yogan Sganzerla
il 6 Ago 2019
Modificato: Yogan Sganzerla
il 6 Ago 2019
A^2 = M
Torsten
il 6 Ago 2019
A = sqrtm(M)
Yogan Sganzerla
il 6 Ago 2019
Perfect! Thank you very much.
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