Which MATLAB function can remove the diagonal elements of a NxN matrix

Do you know which MATLAB function can do the following work: to remove the diagonal elements of a (N+1)x(N+1) matrix to generate a new NxN matrix.
For say, the old matrix is
[ 0 1 2 3
1 0 2 3
1 2 0 3
1 2 3 0 ]
the generated new matrix is
[ 1 2 3
1 2 3
1 2 3 ]

1 Commento

It's not clear what you are asking. In your example, removing the main diagonal still leaves you with (N+1)*N elements, too many to make an N-by-N matrix. You would have to remove the main diagonal plus either the first superdiagonal or the first subdiagonal to end up with N*N elements.

Accedi per commentare.

 Risposta accettata

Your example doesn't add up, as Kenneth mentioned. However, in general you could do something like this:
A = [ 0 1 2 3
1 0 2 3
1 2 0 3
1 2 3 0 ];
A(logical(eye(size(A)))) = []; % Or A = A(~eye(size(A)))
A = reshape(A,4,3); % Or 3,4 or whatever.

2 Commenti

A(A==0)=[]
A = reshape(A,4,3);
Another variation using linear indexing:
m = size(A,1)+1;
A(1:m:end) = [];
A = reshape(A,4,3); % or whatever

Accedi per commentare.

Più risposte (3)

b=triu(a)
b=b(:,2:end)
c=tril(a)
c=c(:,1:end-1)
b+c

1 Commento

this one produces an overlap and doesn't really produce what the other guy wants.

Accedi per commentare.

remove_diagonal = @(t)reshape(t(~diag(ones(1,size(t, 1)))), size(t)-[1 0]);
So :
>> m = magic(5)
m =
17 24 1 8 15
23 5 7 14 16
4 6 13 20 22
10 12 19 21 3
11 18 25 2 9
ans =
23 24 1 8 15
4 6 7 14 16
10 12 19 20 22
11 18 25 2 3
hi, Jinlong Wei
According to your example : Here is a function :
function Z=diagrem(X)
N=size(X);
Z=X;
if N(1)~=N(2)
error('Matrix is not square');
end
for x=1:N(1)
Z(x,x)=0;
end
for y=1:N(1)-1
Z(y,y+1)=0;
end
Z(Z==0)=[];
Z=reshape(Z,N(1)-1,N(2)-1);
It produces exactly your example ,it removes R(i,i) and in the second loop it removes R(j,j+1) with 1<=i<=n , 1<=j<n .

1 Commento

In case your matrix already contains zeros, then change the code by giving Z(x,x) and Z(y,y+1) a NaN value per example or something else then remove them.

Accedi per commentare.

Categorie

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by