I have a text file that I would like to split into an array. Each array cell should be a word, not a sentence or line in the file.

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This is what I got so far. But it does not actually solve my problem.
file= fopen('marktwain.txt','r');
string= fread(file, [1, inf], 'char');
fclose(file);
CStr = dataread('file', 'marktwain.txt', '%s', 'delimiter', '\n');
I have little clue where to go from here.

Risposta accettata

Cedric
Cedric il 17 Mar 2013
Modificato: Cedric il 17 Mar 2013
buffer = fileread('marktwain.txt') ;
words = regexp(buffer, '\<\w+', 'match') ;
.. and we can discuss the pattern if you want to refine the regexp. You could for example have "it's" or "John's" count as single words (and not two) using (EDITED)
words = regexp(buffer, '\<[\w'']+', 'match') ;
The final answer, after the discussion below, is:
buffer = fileread('marktwain.txt') ;
words = regexp(buffer, '\<[\w''\-,]+', 'match') ;
  8 Commenti
Cedric
Cedric il 17 Mar 2013
Modificato: Cedric il 17 Mar 2013
You want the comma to be part of words? If so, you probably figured out now that you can match it with
words = regexp(buffer, '\<[\w'',-]+', 'match') ;
Note that the dash has a special meaning when followed by a literal (it codes a range, like in A-Z that means A to Z), so you have to escape it if it doesn't come last within the []:
words = regexp(buffer, '\<[\w''\-,]+', 'match') ;
This is why I put the comma before the dash in the first expression.

Accedi per commentare.

Più risposte (2)

Walter Roberson
Walter Roberson il 17 Mar 2013
file = fopen('marktwain.txt', 'rt');
CStr = textscan(file, '%s');
fclose(file);
Only problem: you have not defined exactly what a "word" is for your purposes, so the above is going to break things up at whitespace.

Image Analyst
Image Analyst il 17 Mar 2013
Modificato: Image Analyst il 17 Mar 2013
For example:
>> allwords('This is what I got so far. But it does not actually solve my problem.')
ans =
'This' 'is' 'what' 'I' 'got' 'so' 'far' 'But' 'it' 'does' 'not' 'actually' 'solve' 'my' 'problem'

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