Azzera filtri
Azzera filtri

If Regexp matches return 1 otherwise 0 syntax

51 visualizzazioni (ultimi 30 giorni)
Right now I'm using the following to get a boolean result from a regexp. It just doesn't feel right - is there a better way to do this?

Risposta accettata

Walter Roberson
Walter Roberson il 25 Mar 2013
if regexp(myInput,myPattern)
regexp() by default returns a list of indices upon a match, and [] if there are no matches. The list of indices will all be non-zero numbers, and "if" applied to an array of non-zero numbers is considered to be true, just as if all() had been applied to the list. "if" applied to the empty matrix is false. So, you do not need to do any conversion: you can just test regexp() result directly.
  3 Commenti
Walter Roberson
Walter Roberson il 25 Mar 2013
Modificato: Walter Roberson il 25 Mar 2013
~isempty(regexp('aa00aa00', '\d+')) && 1
any(regexp('aa00aa00', '\d+')) && 1
Note: all() instead of any() will not work.

Accedi per commentare.

Più risposte (3)

gwoo il 23 Ago 2021
Modificato: gwoo il 8 Feb 2023
If your input to regex is a cell array (say from collecting from a struct or something), then your output will be a cell array which is not immediately able to be used for logical indexing. You need to convert it from a cell array to a logical array. But many times you'll get empty cells so you can't just use cell2mat because that will implicitly ditch the empty cells and only leave you with the non-empty which doesn't help for indexing. Therefore, I use this following approach to go from an input of a cell array to an output of a logical array.
This is how I get a logical array out of regex:
logicalMatches = ~cellfun('isempty', regexpi({}, stringToBeFound, 'once'));
  1 Commento
James Van Zandt
James Van Zandt il 12 Mag 2022
I have a cell array of strings to test, so I used this method to collect the matches.
K>> ca={'able','baker','charlie','delta','echo','fox','golf','hotel'}
ca =
1×8 cell array
{'able'} {'baker'} {'charlie'} {'delta'} {'echo'} {'fox'} {'golf'} {'hotel'}
K>> regexp(ca,'a')
ans =
1×8 cell array
{[1]} {[2]} {[3]} {[5]} {0×0 double} {0×0 double} {0×0 double} {0×0 double}
K>> ~cellfun('isempty',regexp(ca,'a'))
ans =
1×8 logical array
1 1 1 1 0 0 0 0

Accedi per commentare.

Sean de Wolski
Sean de Wolski il 25 Mar 2013
doc strfind %?

Azzi Abdelmalek
Azzi Abdelmalek il 25 Mar 2013
Maybe you want to use isequal or strcmp


Scopri di più su Characters and Strings in Help Center e File Exchange


Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by