If Regexp matches return 1 otherwise 0 syntax

Hi,

Right now I'm using the following to get a boolean result from a regexp. It just doesn't feel right - is there a better way to do this?

   (size(regexp(myInput,myPattern),1)>0)

[Azzi Abdelmalek]

What do you mean?

Answer 1

[Walter Roberson]

if regexp(myInput,myPattern)

regexp() by default returns a list of indices upon a match, and [] if there are no matches. The list of indices will all be non-zero numbers, and "if" applied to an array of non-zero numbers is considered to be true, just as if all() had been applied to the list. "if" applied to the empty matrix is false. So, you do not need to do any conversion: you can just test regexp() result directly.

[Michael]

Doesn't seem to work with other boolean operators, try:

 regexp('aa00aa00','[0-9]+') && 1

Because two returns are given, it is unhappy, thus the size function, which seems awkward.

[Walter Roberson]

~isempty(regexp('aa00aa00', '\d+')) && 1

or

any(regexp('aa00aa00', '\d+')) && 1

Note: all() instead of any() will not work.

[Michael]

Thanks

Answer 2

[Sean de Wolski]

doc strfind %?

Answer 3

[gwoo]

This is how I get a logical array out of regex:

logicalMatches = ~cellfun('isempty', regexpi({filesInDir.name}, stringToBeFound, 'once'));

[James Van Zandt]

I have a cell array of strings to test, so I used this method to collect the matches.

K>> ca={'able','baker','charlie','delta','echo','fox','golf','hotel'}

ca =

1×8 cell array

{'able'} {'baker'} {'charlie'} {'delta'} {'echo'} {'fox'} {'golf'} {'hotel'}

K>> regexp(ca,'a')

ans =

1×8 cell array

{[1]} {[2]} {[3]} {[5]} {0×0 double} {0×0 double} {0×0 double} {0×0 double}

K>> ~cellfun('isempty',regexp(ca,'a'))

ans =

1×8 logical array

1 1 1 1 0 0 0 0

Answer 4

[Azzi Abdelmalek]

Maybe you want to use isequal or strcmp