creating a matrix from an image

Dear all,
I have an image and when it is read in matlab, it is [m*n] matrix, named M,
I need to create another matrix, named MM, which is exactly M, but the indexes are also listed in that.
In fact, MM has 3 columns and the third column is M (:), but the first two columns are i and j which
i=1:m, j=1:n
Thanks in advance

2 Commenti

Trying to follow you. For this example, spell out what you want MM to be.
M =
1 2 3
4 5 6
7 8 9
10 11 12
>> M(:)
ans =
1
4
7
10
2
5
8
11
3
6
9
12
I need also the index related to data of MM

Accedi per commentare.

 Risposta accettata

Ameer Hamza
Ameer Hamza il 11 Dic 2020
Modificato: Ameer Hamza il 11 Dic 2020
You can use meshgrid() like this
[r,c] = ndgrid(1:size(M,1), 1:size(M,2));
MM = [r(:), c(:), M(:)];

6 Commenti

Shabnam M
Shabnam M il 11 Dic 2020
Modificato: Shabnam M il 11 Dic 2020
Thanks for your kind reply,
Actually I checked your proposal but seems sth is wrong and could not correctly create MM, could you recommend another way?
Rik
Rik il 11 Dic 2020
What error did you get? Or is the result not what you wanted? If so, how is it different?
the results are not right, I compared them with raw data and the data are different
The size of r and c are (n*m), but M is (m*n) and that may create the difference?
Rik
Rik il 11 Dic 2020
Modificato: Rik il 11 Dic 2020
The cause of this inconsistency is that Matlab stores arrays in a column-major form. So if you want to use (:) to transform an array into a vector, you need to make sure the result of your coordinate grid matches that order.
The solution is simple: replace meshgrid by ndgrid. Each of these functions has their use, but ndgrid will give the required order in this case. (you could also sort r and c, but that would be an unnecessary operation)
Yes, ndgrid is more appropriate here. I have edited the answer.

Accedi per commentare.

Più risposte (0)

Richiesto:

il 11 Dic 2020

Modificato:

Rik
il 11 Dic 2020

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by