how to divide the range of given integer number

Hi guys,

Might the deadline of my problem isn't understandable, so here Im explaining my problem.

Im trying to do a range of given integer number between negative and positive (including zero and assume zero is positive ..this just assumption in my case) equally -meaning by equally that the negative number and positive numbers are equally in the two sides, this means :

GivenNumber is an integer parameter (assume it's bigger than 0 )

lets assume I have number 20, GivenNumber=20 so the output is the range : [-10:9] , implicitly the number of numbers/samples in the range [-10:9] are 20 which it's the Givennumber - you can easily see the negative numbers are equally to the positive numbers (including zero as my assumption as positive).

lets assume I have number 10, GivenNumber=10 so output is the range : [-5:4] , implicitly the number of numbers/samples in the range [-5:4] are 10 which it's the Givennumber - you can easily see the negative numbers are equally to the positive numbers (including zero as my assumption as positive).

lets assume I have number 30, GivenNumber=30 so output is the range : [-15:14] , implicitly the number of numbers/samples in the range [-15:14] are 30 which it's the Givennumber - you can easily see the negative numbers are equally to the positive numbers (including zero as my assumption as positive).

So how can I do a function in matlab to get as parameter : GivenNumber , the output is the range as explained above?

Appreciated !

Answer 1

[Walter Roberson]

for GivenNumber = [20 10 30 3 25]
  Walters_Half = GivenNumber/2;
  ceil(-Walters_Half) : ceil(Walters_Half)-1
end

ans = 1×20

-10 -9 -8 -7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7 8 9

●

ans = 1×10

-5 -4 -3 -2 -1 0 1 2 3 4

●

ans = 1×30

-15 -14 -13 -12 -11 -10 -9 -8 -7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14

●

ans = 1×3

-1 0 1

●

ans = 1×25

-12 -11 -10 -9 -8 -7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7 8 9 10 11 12

●

[Jimmy cho]

THANKS!

[Image Analyst]

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