Solving Equations in MATLAB
1 visualizzazione (ultimi 30 giorni)
Mostra commenti meno recenti
trythisone noone
il 27 Dic 2020
Commentato: Ameer Hamza
il 28 Dic 2020
Hello,
I have the following equation.
cos(x) == 0
I want to get two or more possible solutions for the above equation which are 90, 270, and so on. The solve function returns the first solution only.
This technique is important for me to calculate the antenna beamwidths. Any ideas?
Thanks in Adv
0 Commenti
Risposta accettata
Ameer Hamza
il 27 Dic 2020
Modificato: Ameer Hamza
il 27 Dic 2020
There is no general solution to such a problem. A common way is to specify several starting points for the numerical solver and find the unique solutions.
y = @(x) cos(x);
x_range = 0:0.1:4*pi;
y_sol = zeros(size(x_range));
for i = 1:numel(x_range)
y_sol(i) = fzero(y, x_range(i));
end
y_sol = uniquetol(y_sol)
2 Commenti
Più risposte (1)
John D'Errico
il 27 Dic 2020
SOME problems can be handled to find all solutions.
syms x
>> xsol = solve(cos(x) == 0,'returnconditions',true)
xsol =
struct with fields:
x: [1×1 sym]
parameters: [1×1 sym]
conditions: [1×1 sym]
>> xsol.parameters
ans =
k
>> xsol.conditions
ans =
in(k, 'integer')
>> xsol.x
ans =
pi/2 + pi*k
So we learn the set of all solutions takes the form
x = pi/2 + pi*k
where k is an integer.
Sadly, a fully general solution to many problems will not be written so easily. But you can always try.
0 Commenti
Vedere anche
Categorie
Scopri di più su Optimization in Help Center e File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!