Solving Equations in MATLAB

2 visualizzazioni (ultimi 30 giorni)
trythisone noone
trythisone noone il 27 Dic 2020
Commentato: Ameer Hamza il 28 Dic 2020
Hello,
I have the following equation.
cos(x) == 0
I want to get two or more possible solutions for the above equation which are 90, 270, and so on. The solve function returns the first solution only.
This technique is important for me to calculate the antenna beamwidths. Any ideas?
Thanks in Adv

Risposta accettata

Ameer Hamza
Ameer Hamza il 27 Dic 2020
Modificato: Ameer Hamza il 27 Dic 2020
There is no general solution to such a problem. A common way is to specify several starting points for the numerical solver and find the unique solutions.
y = @(x) cos(x);
x_range = 0:0.1:4*pi;
y_sol = zeros(size(x_range));
for i = 1:numel(x_range)
y_sol(i) = fzero(y, x_range(i));
end
y_sol = uniquetol(y_sol)
  2 Commenti
trythisone noone
trythisone noone il 27 Dic 2020
Wow, Nice trick man. It works fine. <3
Ameer Hamza
Ameer Hamza il 28 Dic 2020
I am glad to be of help!

Accedi per commentare.

Più risposte (1)

John D'Errico
John D'Errico il 27 Dic 2020
SOME problems can be handled to find all solutions.
syms x
>> xsol = solve(cos(x) == 0,'returnconditions',true)
xsol =
struct with fields:
x: [1×1 sym]
parameters: [1×1 sym]
conditions: [1×1 sym]
>> xsol.parameters
ans =
k
>> xsol.conditions
ans =
in(k, 'integer')
>> xsol.x
ans =
pi/2 + pi*k
So we learn the set of all solutions takes the form
x = pi/2 + pi*k
where k is an integer.
Sadly, a fully general solution to many problems will not be written so easily. But you can always try.

Tag

Prodotti


Release

R2018a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by