machine eps related query

1 visualizzazione (ultimi 30 giorni)
Sean Doherty
Sean Doherty il 29 Dic 2020
Risposto: Ameer Hamza il 29 Dic 2020
1 + eps > 1
ans =
logical
1
% as expcted
1 + eps
ans =
1.000000000000000
% unexpected, and indeed
1+2.5*eps
ans =
1.000000000000000
any help appreciated

Risposta accettata

Ameer Hamza
Ameer Hamza il 29 Dic 2020
It happens because of finite precision of double() precision datatype: https://en.wikipedia.org/wiki/Double-precision_floating-point_format. Also, because of the fact that MATLAB only prints 16 digits by default, the remaining digits after conversion are not shown (double datatype cannot store more than 16 digits accurately). Try the following
>> fprintf('%0.20f\n', 1+eps)
1.00000000000000022204
>> fprintf('%0.20f\n', 1+2.5*eps)
1.00000000000000044409

Più risposte (0)

Categorie

Scopri di più su Data Type Conversion in Help Center e File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by