evaluate expression

2 visualizzazioni (ultimi 30 giorni)
omnia
omnia il 12 Mag 2011
I have equation y=x*exp( (1-y)/(A*y)*B ) where A nd B constants in my program. I have a vector values for x. How can I evaluate y to plot y versus x ?

Risposta accettata

Andrei Bobrov
Andrei Bobrov il 12 Mag 2011
ezplot(['y-x*exp( (1-y)/(' num2str(A) '*y)*' num2str(B) ')'],[x(1) x(end)])
more
As = ...;
Bs = ...;
y = zeros(size(x));
for j = 1:length(x)
y(j) = fzero(@(y)y-x(j).*exp( (1-y)./(As*y)*Bs ),1);
end
plot(x,y);
  2 Commenti
John D'Errico
John D'Errico il 12 Mag 2011
It is generally not a good idea to convert the numeric values into strings to then pass into ezplot. This loses precision. Far, far better is to use an anonymous function here.
omnia
omnia il 13 Mag 2011
Thank you alot

Accedi per commentare.

Più risposte (1)

Andrew Newell
Andrew Newell il 12 Mag 2011
It would be simpler to provide y and solve for x:
y = -1:0.01:1;
x = y.*exp(- (1-y)./(A*y)*B );
In plotting this, you have to be careful because x goes to Inf or -Inf as y approaches zero from below:
I = y < 0 & abs(x) < 10;
plot(x(I),y(I))
hold on
I = y > 0 & abs(x) < 10;
plot(x(I),y(I))
  1 Commento
omnia
omnia il 13 Mag 2011
yes I know it is easier to provide y and solve for x, but I don't have y. The input to my file is x values.

Accedi per commentare.

Categorie

Scopri di più su Function Creation in Help Center e File Exchange

Prodotti

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by