How can prelocate arrays?

I have an array like A which I want to have all of its elements zero by using Matlab features like zeros(x) function.
for example:
A=[1*3][1*3][1*3][1*3]
Each 1*3 matrix in the array A should have 3 zero.
I know how to make matrices with zero elements e.g zeros(2,3) but I don't know how to use it for array shown above with Matlab features without using simple loops.

3 Commenti

Matt J
Matt J il 23 Apr 2013
Modificato: Matt J il 23 Apr 2013
We can't recognize what kind of array A is. Please execute
>> whos A
and show us the output.
Ayob
Ayob il 23 Apr 2013
Modificato: Ayob il 23 Apr 2013
>> A{1}=[0 0 0]
A = [1x3 double]
>> A{2}=[0 0 0]
A = [1x3 double] [1x3 double]
>> A{3}=[0 0 0]
A = [1x3 double] [1x3 double] [1x3 double]
Does it look clear now?
Matt J
Matt J il 23 Apr 2013
If A is a cell array, then my Answer below will be applicable.

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 Risposta accettata

James Tursa
James Tursa il 23 Apr 2013
This method uses a shared data copy of [0 0 0] to populate the individual cell elements, so it is memory efficient:
A = cell(1, n); % Or whatever size you need
A(:) = {[0 0 0]};
However, pre-allocating cell elements only makes sense in certain cases. E.g., it does not make sense if you are simply going to overwrite the elements with something else downstream in your code. How is the array A going to be used downstream in your code?

3 Commenti

Matt J
Matt J il 23 Apr 2013
Modificato: Matt J il 23 Apr 2013
@Ayob:
This method uses a shared data copy of [0 0 0] to populate the individual cell elements, so it is memory efficient:
Though bear in mind that if you save A to a .mat file, the data sharing is lost. Also, this method assumes that all A{i} are the same size. If so, it makes little sense to be using a cell array to hold A's data.
Ayob
Ayob il 23 Apr 2013
It doesn't work in my program: MATLAB error: ??? The following error occurred converting from cell to double:
Error using ==> double
Conversion to double from cell is not possible.
Error in ==> ThesisMLS at 81
A(:)={[0 0 0]};
James Tursa
James Tursa il 24 Apr 2013
Be sure to do A = cell(1, n) first.

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Più risposte (1)

Matt J
Matt J il 23 Apr 2013
Modificato: Matt J il 23 Apr 2013
This might be what you need
out = cellfun(@(c) zeros(size(c)), A, 'uni',0),
It has shorter syntax than a loop, but is not faster.

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