Replacing a for loop with matrix multiplication
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Jessica Nadalin
il 1 Feb 2021
Commentato: Bruno Luong
il 1 Feb 2021
In the problem I have here, x is a 2x300 matrix and SIG is a 2x2 matrix.
What I'm looking for is a 1x300 vector, where the ith entry corresponds to x(:,i)'*inv(SIG)*x(:,i). I've written this out in a for loop below:
ans = zeros(1,size(x,2));
for i = 1:size(x,2)
ans(i) = x(:,i)'*inv(SIG)*x(:,i);
end
but I think there must be a way to make this more efficient with some sort of matrix multiplication--I just can't figure it out.
Any help appreciated!
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James Tursa
il 1 Feb 2021
Modificato: James Tursa
il 1 Feb 2021
result = sum(x.*(inv(SIG)*x));
or
result = sum(x.*(SIG\x));
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