Remove everything outside a defined area

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Hi,
I have to study the response of a cellular graded material with Abaqus, and to recreate the geometry, I'm using the Voronoi function of Matlab.
I need to cut out everything outside the area that's being defined with the letter "s", but I don't know how.
The code to recreate the area and the voronoi structure is this:
clear all; close all; clc
%Defining the area "s" I want to use to cut the portion I need
s = table([0; 0; 30; 30],[0; 10; 10; 0], ones(4,1),...
'VariableNames',{'X','Y','Z'},'RowNames',{'A','B','C','D'});
patch(s.X,s.Y,s.Z);
axis equal;
hold on
%Defining a minimum distance that the nodes have to maintain
minAllowableDistance = 0.5;
%Defining the number of nodes/points I want to generate
numberOfPoints = 2000;
%Generating the x and y coordinates randomly
x = 30*rand(1,numberOfPoints);
y = 10*rand(1,numberOfPoints);
%Here there is the cicle needed to place the points at a given distance
%from each other
keeperX = x(1);
keeperY = y(1);
counter=1;
for k = 1 : numberOfPoints
thisX = x(k);
thisY = y(k);
distances = sqrt((thisX-keeperX).^2 + (thisY - keeperY).^2);
minDistance = min(distances);
if minDistance >= minAllowableDistance
keeperX(counter) = thisX;
keeperY(counter) = thisY;
counter = counter + 1;
end
end
%Creating the voronoi structure.
voronoi(keeperX,keeperY);

Risposta accettata

darova
darova il 17 Feb 2021
Try initmesh to triangulate
  3 Commenti
darova
darova il 18 Feb 2021
YOu can do something like
ind = 0<y && y<10; % find indices outside rectangle
x(ind) = []; % remove data
y(ind) = [];
Edmondo D'Ercole
Edmondo D'Ercole il 25 Feb 2021
Actually this is how you solve my question. THANK YOU! The problem was with how I used the Voronoi function. I solved it this way:
[vx,vy]=voronoi(keeperX,keeperY);
ind = vx<0 | vx>30;
vx(ind) = [];
vy(ind) = [];
ind = vy<0 | vy>10;
vx(ind)=[];
vy(ind)=[];
With this, I generate the vertices of the Voronoi structure, and then cut off the vertices outside my area of interest.

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