calling one GUI from another GUI?
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hey!!
i am trying to call one gui from another gui using this code for the push buttons suppose from GUI_1 i have to call GUI_2
pushbutton1_Callback(GUI_2);
GUI_2.m;
errordlg('Ok the call back is linked');
its working for one of the gui's but not for the other. this is the error which m getting
*Error in sample>pushbutton2_Callback (line 94)
pushbutton2_Callback(start_gui_single_mode);
Error in gui_mainfcn (line 96)
feval(varargin{:});
Error in sample (line 42)
gui_mainfcn(gui_State, varargin{:});
Error in @(hObject,eventdata)sample('pushbutton2_Callback',hObject,eventdata,guidata(hObject))
Error while evaluating uicontrol Callback*
for the source code please refer:
i am new to matlab, please help!!
2 Commenti
Jan
il 6 Mag 2013
This is the part of the error message, which explaines where the problem occurred. But the part is missing, which tells what the error is.
Jan
il 6 Mag 2013
The reference to page, which contains about 24 links, is not helpful. Of course the readers of this forum will not read all of them to find out more.
Risposte (1)
Jan
il 6 Mag 2013
You call a function by using its name without file extension:
GUI_2; % Instead of: GUI_2.m;
I'm not sure if this causes your problem, but it is at least not correct.
11 Commenti
niyeti
il 6 Mag 2013
Jan
il 6 Mag 2013
Unfortunately you do not tell us, what the error message tells you, but only, that the error appears in line 94. But we cannot know, which is the line 94, as I have mentioned in my comment already.
pushbutton1_Callback(GUI_2);
This looks strange also. But without a crystal ball I cannot know what this line should do. When GUI_2 is a function call, it is not really well placed in this line - perhaps.
Please do not let us guess the details.
Babak
il 6 Mag 2013
Can you put a debug button before the line
start_gui_single_mode;
and tell us if your code can reach this line at all?
Babak
il 6 Mag 2013
why do u need to call the function
pushbutton2_Callback(start_gui_single_mode);
from inside itself?
niyeti
il 6 Mag 2013
Babak
il 6 Mag 2013
This is not right:
function pushbutton2_Callback(hObject, eventdata, handles)
//....
pushbutton2_Callback(start_gui_single_mode);
you cannot call pushbutton2_Callback function inside itself. You can call another GUI (child) from inside a parent GUI, but calling same function from inside itself is problematic.
niyeti
il 7 Mag 2013
Céldor
il 7 Mag 2013
I totally agree with Babak. It is very strange when you are calling a callback from the callback itself. Even though, it is a regular function, it is supposed to be called when an event occurs!!! I am also not experienced but this is how I understand the event/callback mechanism. Besides, you have three parameters at the callback definition but you seem to pass only one when you actually call the function; and your parameters during the call is a function name like you would like to pass a function handle. It really looks wrong to me.
Sarala Swain
il 11 Lug 2016
just use close(filename) filename(to which u want to open)
dear Jan
I have two GUI , one is vefrf, and other is Printedit. i saved at the desktop
I want to open GUI Printedit when use a push button.
I used command: (as you recommanded above)
Printedit;
in function Callback of push buttoon in GUI 1. And, it worked fine.
And then, i cut all file (m.file and fig.file of two GUIs to a E:\ ....(not is C:\)
And, now, when i run GUI, click on push button in GUI 1, Matlab didn't open GUI 2.
Why ???????
Please help me!
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