how to choose the value?

1 visualizzazione (ultimi 30 giorni)
win
win il 14 Mag 2013
i have some data. see below if true
l1 = input('bus connection(choose one number from 1 to 30) = ');
bus1 = [2 3];
bus2 = [1 4 6 5];
bus3 = [1 4];
bus4 = [2 3 6 12];
bus5 = [2 7];
bus6 = [2 4 7 8 9 10 28];
bus7 = [5 6];
bus8 = [6 28];
bus9 = [6 10 11];
bus10 = [6 9 17 20 21 22];
bus11 = 9;
bus12 = [4 13 14 15 16];
bus13 = 12;
bus14 = [12 15];
bus15 = [12 14 18 23];
bus16 = [12 17];
bus17 = [16 10];
bus18 = [15 19];
bus19 = [18 20];
bus20 = [10 19];
bus21 = [10 22];
bus22 = [10 21 24];
bus23 = [15 24];
bus24 = [22 23 25];
bus25 = [24 26 27];
bus26 = 25;
bus27 = [25 28 29 30];
bus28 = [6 8 27];
bus29 = [27 30];
bus30 = [29 27];
end
when i press 1 it display bus1 matrix also when i press 2 it show bus2 matrix and bus3,bus4 etc., please anyone help me
  2 Commenti
Thomas
Thomas il 14 Mag 2013
Goodwin, your code will not work as it is. I assume you want the user to input the number and then you want the corresponding bus matrix to show up..
Where do you compare what the user has entered to what you want to look up? you could do this by a number of 'if' statements (just think about it.. ) or use switch case..
win
win il 14 Mag 2013
thanks bro.........

Accedi per commentare.

Risposta accettata

Thomas
Thomas il 14 Mag 2013
An example of how to use switch case: adapt for your particular case
busNum=input('Enter the bus number:');
switch busNum
case 1
disp('2 3')
case 2
disp('1 4 6 5')
end

Più risposte (2)

Jan
Jan il 14 Mag 2013
Storing the values in different variables is a bad idea. Better use an array:
bus = {[2 3], ...
[1 4 6 5], ...
[1 4], ...
etc. };
l1 = input('bus connection(choose one number from 1 to 30) = ');
disp(bus{l1});
  1 Commento
win
win il 14 Mag 2013
thanks bro...... i learned something here. thanks for all of you

Accedi per commentare.


Jurgen
Jurgen il 14 Mag 2013
I suggest you concatenate the numerical input l1 with the string 'bus'. Then display the content with display(). E.g.
X = ['bus' l1];
display(X)
  5 Commenti
Jurgen
Jurgen il 15 Mag 2013
Well it should work for this simple case?
José-Luis
José-Luis il 15 Mag 2013
It is not a matter of it working or not. Please look at this previous discussion.

Accedi per commentare.

Prodotti

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by