Convolution problem
2 visualizzazioni (ultimi 30 giorni)
Mostra commenti meno recenti
hello to all
in this code we have an ofdm signal(60 MHZ),with length of 4096x1 (Pxx) and a power line model 0 to 80 Mhz with length of 1x161
the two parameters are shown in frequency domain
we have tried to get the plot after the ofdm signal is transmited threw the power line filter by convolution in time domain , or by multiplexing in frequensy domain
thank alot
the code :
clear all
%%%%%%%%%%%%%%%%%%%%%% O F D M S I G N A L %%%%%%%%%%%%%%%%%%%%%%
nFFTSize =64 ;
% for each symbol bits a1 to a52 are assigned to subcarrier
% index [-30 to -1 1 to 30]
subcarrierIndex = [-30:-1 1:30];
nBit = 2500;
ip1 = rand(1,nBit) >0.5;
ip2=rand(1,nBit) >0.5;
ip=[ip1;ip2] > 0.5; % generating 1's and 0's
nBitPerSymbol = 60;
nSymbol = ceil(nBit/nBitPerSymbol);
j=sqrt(-1)
% QBPSK modulation
% bit00 --> 1
% bit01 --> 1+j
% bit10 -->-1
% bit11 -->-1-j
t1 = ip1==1;
t2 = ip2==1;
ipMod(t1 & t2) = -(1+1i); %11
ipMod(~t1 & t2) = 1+1i; %01
ipMod(t1 & ~t2) = -1; %10
ipMod(~t1 & ~t2) = 1; %00
ipMod = [ipMod zeros(1,nBitPerSymbol*nSymbol-nBit)];
ipMod = reshape(ipMod,nSymbol,nBitPerSymbol);
figure(2)
plot(ipMod)
st = []; % empty vector
for ii = 1:nSymbol
inputiFFT = zeros(1,nFFTSize);
% assigning bits a1 to a52 to subcarriers [-30 to -1, 1 to 30]
inputiFFT(subcarrierIndex+nFFTSize/2+1) = ipMod(ii,:);
% shift subcarriers at indices [-30 to -1] to fft input indices [38 to 63]
inputiFFT = fftshift(inputiFFT);
outputiFFT = ifft(inputiFFT,nFFTSize);
% adding cyclic prefix of 16 samples
outputiFFT_with_CP = [outputiFFT(49:64) outputiFFT];
st = [st outputiFFT_with_CP];
end
close all
fsMHz = 60;
[Pxx,W] = pwelch(st,[],[],4096,20);
figure(3)
plot([-2048:2047]*fsMHz/4096,10*log10(fftshift(Pxx)));
xlabel('frequency, MHz')
ylabel('power spectral density')
title('Transmit spectrum OFDM (based on 802.11a)');
%%%%%%%%%%%%%%%%%%%%%%POWER LINE COMMUNICATION TRANSFER FUNCTION %%%%%%%%%%%%%%%%%%%%%%
w=0:0.5*10^6:80*10^6; % [Hz]
l=5 ; % [meter]
zl=50 ; % [ohm/meter]
zs=50 ; % [ohm/meter]
R=1.9884 ; % [ohm/meter]
G=0.01686*10^-9 ; % [mho/meter]
C=0.13394*10^-9 ; % [farad/meter]
L=362.81*10^-9 ; % [henrry/meter]
zc=sqrt((R+j.*w.*L)./(G+j.*w.*C)); % characteristic impedance [ohm]
gama=sqrt((R+j.*w.*L).*(G+j.*w.*C)); % propagation constant
a=cosh(gama.*l);
b=zc.*sinh(gama.*l);
c=(1./zc).*sinh(gama.*l);
d=cosh(gama.*l);
H= zl./((a.*zl)+b+(c.*zl.*zs)+(d.*zs)); %transfer function [Vl/Vs]
figure(1)
plot(w,20*log10(H)) % clean
xlabel('frequency [Hz]');
ylabel('Transfer function magnitude H(f) [dB]');
figure(5)
subplot(2,1,1)
plot(w,20*log10(H+0.001*[randn(1,length(H)) + j*randn(1,length(H))])) % plus random noise
xlabel('frequency [Hz] ');
ylabel('Transfer function + random noise [dB]');
subplot(2,1,2)
plot(w,20*log10(H+0.001*wgn(1,length(H),-10))) % plus white gaussian noise
xlabel('frequency [Hz] ');
ylabel('Transfer fuction + wgn [dB]');
y=conv(Pxx,H)
figure(4)
plot(20*log10(y))
4 Commenti
Risposta accettata
Daniel Shub
il 17 Mag 2011
Convolution of time domain signals is the same as multiplication of frequency domain signals. You cannot simply multiple Pxx and H since they have different sizes. You could take the ifft of both, conv and then take the fft of the result. Better would be to use W from pwelch instead of w in calculating H (you need to adjust for the sampling rate).
3 Commenti
Daniel Shub
il 17 Mag 2011
Yes, you can just multiple in frequency, but NO you cannot just zero pad. You need to create H and Pxx with the same spectral spacing. Think about your W and w variables and what they represent.
To get the plot in the frequency domain try plot(W, 20*log10(y)).
On a side note, do you really want 20*log10 with Pxx (an estimate of power).
Più risposte (0)
Vedere anche
Categorie
Scopri di più su Digital Filtering in Help Center e File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!