Azzera filtri
Azzera filtri

Indexing arrays of varying dimensionality.

2 visualizzazioni (ultimi 30 giorni)
I have to handle arrays of varying dimensionality in one loop, and I have to index individual elements of those arrays.
From what I have seen in the general help, the only solution seems to be to do a stupid and unflexible switch-case-like approach, such as
sz=size(arr);
switch length(sz)
case 1:
ind1=calc_ind(1);
elem_val=arr(ind1);
case 2:
ind1=calc_ind(1);
ind2=calc_ind(2);
elem_val=arr(ind1,ind2);
case 3:
ind1=calc_ind(1);
ind1=calc_ind(2);
ind3=calc_ind(3);
elem_val=arr(ind1,ind2,ind3);
end
This makes it impossible to handle arrays of arbitrary dimensionality and is also very stupid and repetitive.
Using linear indices doesn't seem to help, because also sub2ind() needs different calls for each dimensionality.
Is there not an easier solution. like
sz=size(arr);
for d=1:length(sz)
ind_arr(d)=calc_index(d);
end
LinIndex=sub2ind(sz,ind_arr);
elem_val=arr(LinIndex);

Risposta accettata

Stephen23
Stephen23 il 2 Mar 2021
Modificato: Stephen23 il 23 Feb 2022
  1 Commento
Stephen23
Stephen23 il 2 Mar 2021
Complete working example:
arr = rand(7,6,5,4,3,2);
idx = [5,3,4,4,1,1];
tmp = num2cell(idx);
x = arr(tmp{:})
x = 0.2769
y = arr(5,3,4,4,1,1)
y = 0.2769

Accedi per commentare.

Più risposte (1)

Lionel Pöffel
Lionel Pöffel il 3 Mar 2021
Thanks, that works beautifully!

Prodotti

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by