How to evaluate dirac function in matlab?
5 visualizzazioni (ultimi 30 giorni)
Mostra commenti meno recenti
I have this problem in matlab 2011a that I can not evaluate dirac function of higher order. In other words, the symbolic expression works well:
syms x;
diff(dirac(x),x)
ans =
dirac(x, 1)
However, it can not evaluate dirac(x, 1) when x is double:
>> dirac(1, 1)
??? Error using ==> dirac
Too many input arguments.
What should I do? Is there any code available ?
I can evaluate this in Maple but it is hard to believe that matlab doesn't prepared for this simple problem.
0 Commenti
Risposte (2)
Iman Ansari
il 23 Mag 2013
Modificato: Iman Ansari
il 23 Mag 2013
syms x;
y=diff(dirac(x),x)
subs(y,1)
0 Commenti
Youssef Khmou
il 23 Mag 2013
hi
The dirac function accepts only one argument (at least for earlier versions than yours) however, if you do not have the symbolic toolbox you can program your own function and put "1" in "0" instead of +infinity .
-First solution :
t=-10:0.001:10;
y=dirac(t);
figure, plot(t,y);
dy=diff(y)./diff(t);
figure, plot(t(1:end-1),dy,'r')
-Second solution :
function z=Dirac(t)
N=length(t);
z=zeros(size(t));
for n=1:N
if t(n)==0
z(n)=1;
end
end
Adjust this function for later use ....
0 Commenti
Vedere anche
Categorie
Scopri di più su Numbers and Precision in Help Center e File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!