Alternatives to using polyfit and polyval functions??

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Ben Spurr
Ben Spurr il 12 Mar 2021
Commentato: Ben Spurr il 12 Mar 2021
%% This Code looks to find wether a quadratic or linear plot gives a lower error for a set of given data.
%% First clearing anything previous data in the script
clc; clear all; close all;
%% Start
%Input Values
d10 = [0.0024; 0.0025; 0.0056; 0.0083; 0.0262; 0.0302; 0.0413; 0.0428];
k = [2.29E-04; 2.28E-04; 2.40E-04; 1.21E-04; 2.58E-03; 4.92E-03; 5.16E-03; 7.00E-03];
% Plot for linear and polynomial
p1 = polyfit(d10, k, 1);
p2 = polyfit(d10, k, 2);
plot(d10, k, 'o');
hold on
plot(d10, polyval(p1, d10), 'b-');
plot(d10, polyval(p2, d10), 'r--');
xlabel('d10 [mm]', 'fontsize', 20);
ylabel('k [mm/sec]','fontsize',20);
xlim([0, 0.05]);
ylim([0, 0.01]);
% Residual Error linear
kfit1 = polyval(p1,d10);
kresid1 = k - kfit1;
SSresid1 = sum(kresid1.^2);
disp(['R Squared Value: ',num2str(SSresid1)]);
% Residual Error quadratic
kfit2 = polyval(p2,d10);
kresid2 = k - kfit2;
SSresid2 = sum(kresid2.^2);
disp(['R Squared Value: ',num2str(SSresid2)]);
if SSresid2 > SSresid1
disp(['Linear has a better SSresid value of: ', num2str(SSresid1)]);
else
disp(['Quadratic has a better SSredid value of: ', num2str(SSresid2)]);
end
This is my code I wrote which finds whether a linear or quadratic plot is better for the given data. Im not looking to use the polyfit and polyval inbuilt functions, can anyone help find an alternative?

Risposte (1)

Jan
Jan il 12 Mar 2021
Modificato: Jan il 12 Mar 2021
POLYFIT and POLYVAL are simple functions. If your teacher wants you to write them by your own, I assume, that this was a topic in your lessons.
This is some code for the fitting:
% Used: x, y, n = degree of polynomial
V = ones(numel(x), n + 1); % Construct Vandermonde matrix:
for j = n:-1:1
V(:, j) = V(:, j + 1) .* x(:);
end
[Q, R] = qr(V, 0); % Solve least squares problem:
p = transpose(R \ (transpose(Q) * y(:))); % Same as: (V \ y)'
For POLYVAL use the Horner scheme.

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