Fractal in matlab and image segmentation
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Here is segmentation process and at the last i wanna count the fractal dimension of the last figure. But it goes error. Can somebody help me to fix this. Thanks
image_folder = 'C:\Users\ADMIN\Matlab\Implementasi\Week7-1\output';
outfolder = 'C:\Users\ADMIN\Matlab\Implementasi\Week7-1\segmentasi';
if ~isdir(outfolder); mkdir(outfolder); end
files = dir(fullfile(image_folder, '*.jpg'));
%I presume it has the variable map in it
for iFiles = 1:numel(files)
thisfilename = fullfile(files(iFiles).folder,files(iFiles).name);
[~, basename, ext] = fileparts(image_folder);
citra = imread(thisfilename);
%change to grayscale
grayimg = rgb2gray(citra);
figure, fig2=imshow(grayimg);
%change to green channel
green_channel = citra(:,:,2);
figure, fig3=imshow(green_channel);
%change to CLAHE (Contrast Limited Adaptive Histogram Equalization)
CLAHE = adapthisteq(green_channel);
figure, fig4=imshow(CLAHE);
ER = edge(CLAHE, 'canny');
EG = edge(CLAHE, 'canny');
EB = edge(CLAHE, 'canny');
anyedge = ER | EG | EB;
figure, fig5=imshow(anyedge)
size(fig5)
% fig = figure;
outfile = fullfile(outfolder, sprintf('%s-coba-%03d.jpg', basename, iFiles));
saveas(fig5, outfile);
% yang dihitung dimensinya yaitu citra hasil segmentasi
[n, r] = fboxcount(figure,'slope');
%Perhitungan dimensi
df = -diff(log(n))./diff(log(r));
%Menampilkan hasil dimensi
disp(['Df= ' num2str(mean(df(4:8)))]);
% end
end
1 Commento
Keerthi Reddy
il 12 Lug 2023
Can you please provide the specific error message you are recieving? Also can you please provide which part of the code is causing the error?
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