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for loop reference solution (from coursera) question

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Sorry if this is a stupid question, but I am pretty new to matlab, looking at this solution at the loop "for n=1:nint@" I can't see how this works as there isn't a variable allocated "n", just "nx" and "ny". and the other functions in the loop are functions of 'Z' or 'z'.
Many thanks for your help.
  1 Commento
Russel Burgess
Russel Burgess il 14 Mar 2021
The for loop expression creates the variable, i.e.,
for n=1:nit
Will create a variable, n, initially set to 1. n is persistent, i.e., it will still exist after the foor loop is done - with the value nit, assuming nothing caused the for loop to break out early.

Accedi per commentare.

Risposte (1)

Shubham Rawat
Shubham Rawat il 17 Mar 2021
Hi Sara,
Comment is correct only inside for loop the variable n is instantiated.
You may look into this documentation for further help:
Hope this Helps!

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