Azzera filtri
Azzera filtri

matrix for loop question

2 visualizzazioni (ultimi 30 giorni)
jana
jana il 30 Mag 2013
Suppose I have a matrix [1 2 3 5;1 3 4 5]. Each row represents a path and each column represents the nodes of that path. For example: for row 1 : 1-2-3-5 is a path with nodes 1, 2 ,3, 5(where one is the start node and 5 is the end node). I want to consider an arc and arcs following that arc. For example: I want to consider (1,2) and (2-3) and assign a cost to it. I wrote a code but its showing an error. please help!
for kkp = 1:size(R{ip},1) % R{ip} is my path matrix
for jjp = 1:size(R{ip},2)-1
for iip = 1:size (R{ip,2} -2)
up = R{ip}(kkp,jjp);
vp = R{ip}(kkp,jjp+1);
wp = R{ip}(kkp,jjp+2);
cost1 = wt(up,vp); %wt(i,j) is a cost matrix that i already inputed.
cost 2 = wt(vp,wp);
end
end
end

Risposta accettata

Eugene
Eugene il 30 Mag 2013
You're indexing 'R' as a 1-D cell array at the start however in the third line you start indexing the 2nd dimension.
for iip = 1:size (R{ip,2} -2)
I think you meant
for iip = 1:size(R{ip},2) - 2
And a typo at (no space between 'cost' and '2'):
cost 2 = wt(vp,wp);
  2 Commenti
jana
jana il 30 Mag 2013
I've made the correction but it is still showing an error. My cost2 outpput is coming as zero but that is not right.
my wt matrix is :
wt =[0 2 4 0;1 0 5 3;4 5 0 5;0 3 5 0];
so if for path 1-2-3-4 cost1 should be 2 and cost2 should be 5 (for 2-3) and 5 (for 3-4) .
jana
jana il 30 Mag 2013
nevermind..I fixed it. Thanks.

Accedi per commentare.

Più risposte (0)

Tag

Non è stata ancora inserito alcun tag.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by